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Eddi Din [679]
3 years ago
11

Consider the SCl2 molecule. (a) What is the electron config- uration of an isolated S atom? (b) What is the electron con- figura

tion of an isolated Cl atom? (c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in SCl2? (d) What valence orbitals, if any, remain unhybrid- ized on the S atom in SCl2?
Chemistry
1 answer:
iragen [17]3 years ago
7 0

Answer:

(a) 1s² 2s² 2p⁶ 3s² 3p⁴

(b) 1s² 2s² 2p⁶ 3s² 3p⁵

(c) sp³

(d) No valence orbital remains unhybridized.

Explanation:

<em>Consider the SCl₂ molecule. </em>

<em>(a) What is the electron configuration of an isolated S atom? </em>

S has 16 electrons. Its electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁴.

<em>(b) What is the electron configuration of an isolated Cl atom? </em>

Cl has 17 electrons. Its electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁵.

<em>(c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in SCl₂? </em>

SCl₂ has a tetrahedral electronic geometry. Therefore, the orbital 3s hybridizes with the 3 orbitals 3 p to form 4 hybrid orbital sp³.

<em>(d) What valence orbitals, if any, remain unhybridized on the S atom in SCl₂?</em>

No valence orbital remains unhybridized.

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agasfer [191]

Answer:

The equilbrium constant is 179.6

Explanation:

To solve this question we can use the equation:

ΔG = -RTlnK

<em>Where ΔG is Gibbs free energy = 12.86kJ/mol</em>

<em>R is gas constant = 8.314x10⁻³kJ/molK</em>

<em>T is absolute temperature = 298K</em>

<em>And K is equilibrium constant.</em>

Replacing:

12.86kJ/mol = -8.314x10⁻³kJ/molK*298K lnK

5.19 = lnK

e^5.19 = K

179.6 = K

<h3>The equilbrium constant is 179.6</h3>

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3 years ago
Calculate the number of molecules in a deep breath of air whose volume is 2.15 L at body temperature, 37 ∘C, and a pressure of 7
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PV = nRT 
R = 0.0821 L * atm / mol * K 
(ideal gas constant) 

First, convert 735 torr to atm. Divide by 760. 
(1 atm = 760 torr) 

735 torr * 1 atm / 760 torr = 0.967 atm 
Then, convert 37 C to Kelvin. Just add 273. 
37 C = 310K 

n = PV / RT 
= (0.967)(2.07) / (0.0821)(310) 
= 0.0786 mol 

<span>0.0786 mol * 6.02 * 10^23 molecules / 1 mol = 4.73 * 10^22 molecules </span>
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What are some<br> double replacement reactions you see every day
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Answer:

  • Sodium Bicarbonate (β-3) + Vinegar
  • Lead Nitrate + Potassium iodide

Explanation:

Baking Soda and vinegar cause an explosion, in which the bicarbonate and vinegar are replaced by nitrate (∨) and oxide (Ф.) When you combine lead nitrate (Δω) with potassium iron, you also see the ingredients you combined disappear, which shall cause a replace reaction

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What is the main difference between protrons and neutrons?
m_a_m_a [10]

Answer:

protons are positive and neutrons are neutral, both are in nucleus

Explanation:

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How many formula units are in 239.2g of <br> Br2<br> MgCl2<br> H2O<br> Fe
Oksana_A [137]

The formula units in the substances are as follows:

  • Br2 = 8.99 × 10^23 formula units
  • MgCl2 = 1.51 × 10^24 formula units
  • H2O = 2.57 × 10^24 formula units
  • Fe = 2.57 × 10^24 formula units

<h3>How many moles are in 239.2 g of the given substances?</h3>

The moles of the substances are determined from their molar mass.

Molar mass of the substances is given as follows:

  • Br2 = 160 g/mol
  • MgCl2 = 95 g/mol
  • H2O = 18 g/mol
  • Fe = 56 g/mol

Formula units = mass/molar mass × 6.02 × 10^23

The formula units in the substances are as follows:

  • Br2 = 239.2/160 × 6.02 × 10^23 = 8.99 × 10^23 formula units
  • MgCl2 = 239.2/95 × 6.02 × 10^23 = 1.51 × 10^24 formula units
  • H2O = 239.2/18 × 6.02 × 10^23 = 2.57 × 10^24 formula units
  • Fe = 239.2/56 × 6.02 × 10^23 = 2.57 × 10^24 formula units

In conclusion, the number of formula units is derived from the moles and Avogadro number.

Learn more about formula units at: brainly.com/question/24529075

#SPJ1

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