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Eddi Din [679]
3 years ago
11

Consider the SCl2 molecule. (a) What is the electron config- uration of an isolated S atom? (b) What is the electron con- figura

tion of an isolated Cl atom? (c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in SCl2? (d) What valence orbitals, if any, remain unhybrid- ized on the S atom in SCl2?
Chemistry
1 answer:
iragen [17]3 years ago
7 0

Answer:

(a) 1s² 2s² 2p⁶ 3s² 3p⁴

(b) 1s² 2s² 2p⁶ 3s² 3p⁵

(c) sp³

(d) No valence orbital remains unhybridized.

Explanation:

<em>Consider the SCl₂ molecule. </em>

<em>(a) What is the electron configuration of an isolated S atom? </em>

S has 16 electrons. Its electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁴.

<em>(b) What is the electron configuration of an isolated Cl atom? </em>

Cl has 17 electrons. Its electron configuration is 1s² 2s² 2p⁶ 3s² 3p⁵.

<em>(c) What hybrid orbitals should be constructed on the S atom to make the S-Cl bonds in SCl₂? </em>

SCl₂ has a tetrahedral electronic geometry. Therefore, the orbital 3s hybridizes with the 3 orbitals 3 p to form 4 hybrid orbital sp³.

<em>(d) What valence orbitals, if any, remain unhybridized on the S atom in SCl₂?</em>

No valence orbital remains unhybridized.

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The reaction between zinc and silver nitrate is

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Moles of Zn = m /M = 599 /65 = 9.2 mol

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Which atom’s ionization energy is greater than that of phosphorus (P)? A. Ba B. K C. As D. Cl
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<h3>Answer:</h3>

                   Chlorine (Cl)

<h3>Explanation:</h3>

                           Ionization Energy is defined as, "the minimum energy required to knock out or remove the valence electron from valence shell of an atom".

Trends in Periodic table:

               <em>Along Periods:</em>

                                        Ionization Energy increases from left to right along the periods because moving from left to right in the same period the number of protons (atomic number) increases but the number of shells remain constant hence, resulting in strong nuclear interactions and electrons are more attracted to nucleus hence, requires more energy to knock them out.

               <em>Along Groups:</em>

                                        Ionization energy decreases from top to bottom along the groups because the number of shells increases and the distance between nucleus and valence electrons also increases along with increase in shielding effect provided by core electrons. Therefore, the valence electrons experience less nuclear attraction and are easily removed.

<h3>Conclusion:</h3>

                   As Barium is present down the group and to the left of periodic table, K present at the left of the periodic table, Arsenic present below Phosphorous will have less ionization energies as compared to P. Hence, only Chlorine present at the right extreme of periodic table and right to P will have greater Ionization energy.

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