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trapecia [35]
1 year ago
10

Does any solid Ag₂CrO₄ form when 2.7x10⁻⁵g of AgNO₃ is dissolved in 15.0 mL of 4.0x10⁻⁴MK₂CrO₄?

Chemistry
1 answer:
e-lub [12.9K]1 year ago
3 0

Molarity of Ag+ is less than the molar solubility thus ppt will not occur.

Balanced reaction-:

<h3>2AgNO3(aq)+K2CrO4(aq)→Ag2CrO4(s)+2KNO3(aq)</h3>

Moles of AgNO3=mass(g)molar mass (g/mol) =2.7×10−5g / 169.86 gmol

=1.589⋅10^−7 mol

Molarity of Ag+=moles of solute(L)=1.589⋅10−7 mol0.015 L=1.059⋅10−5M

Ksp of Ag2CrO4

=[Ag+]2[CrO42−]

1.2⋅10−12=[2s]2[s]

4s3=1.2⋅10−12

s=6.69⋅10−5 M

Molarity of Ag+ is less than the molar solubility thus ppt will not occur.

<h3>What is the molarity calculation formula?</h3>

The volume of solvent required to dissolve the provided solute is multiplied by the ratio of the moles of the solute whose molarity has to be computed. (M=frac{n}{V}) The molality of the solution that needs to be computed in this case is M. n is the solute's molecular weight in moles.

Learn more about Molarity:

brainly.com/question/8732513

#SPJ4

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Compare 1 mole of H2, 1 mole of O2 and 1 mole of F2
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(a)  As per the mole concept, one mole of any atom contains 6.022 \times 10^{23} atoms or molecules, that is, Avogadro's number of atoms.

Therefore, 1 mole of H_{2} = 2 \times 6.022 \times 10^{23} molecules

                                           = 1.2044 \times 10^{23} molecules

   1 mole of O_{2} = 2 \times 6.022 \times 10^{23} molecules

                                    = 1.2044 \times 10^{23} molecules

   1 mole of F_{2} = 2 \times 6.022 \times 10^{23} molecules

                                    = 1.2044 \times 10^{23} molecules

Hence, there are equal number of molecules present in the given atoms.

(b)   Mass of each given atom will be calculated as follows.

                Mass = no. of moles × molar mass

As one molecule of H_{2} contains 2 atoms of hydrogen.

So, mass of 1 mole of H_{2} = 2 mol \times 1.008 g/mol

                                                     = 2.016 g

      mass of 1 mole of O_{2} = 2 mol \times 15.999 g/mol

                                                     = 31.996 g

      mass of 1 mole of F_{2} = 2 mol \times 18.998 g/mol

                                                     = 37.996 g

Thus, we can conclude that F_{2} has the greatest mass.

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