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zepelin [54]
3 years ago
6

80 POINTSSS

Physics
1 answer:
Semenov [28]3 years ago
7 0

Answer:

closed parallel circuit

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Three charges 1.5*10-6, 3*10-6, -3*10-6 are placed at three vertices of an equilateral triangle of side 30cm. Find the net force
gulaghasi [49]

Answer:

F = 0N

Explanation:

The force between two charges is given by

F=k\frac{q_1q_2}{r^2}

where r is the distance between the charges and K is the Coulomb's constant

(k=8-89*10^9Nm^2/C^2)

The force in the first charge is only the sum of the forces due to the other charges. Hence we have

F_T=F_1+F_2=k\frac{q_2q_1}{r^2}+k\frac{q_3q_1}{r^2}

F_T=(8.89*10^9\frac{Nm^2}{C^2})\frac{(3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}+(8.89*10^9\frac{Nm^2}{C^2})\frac{(-3*10^{-6}C)(1.5*10^{-6}C)}{(0.3m)^2}\\\\F_T=0.445N-0.445N=0N

Ft=0N

Hope this helps!!

5 0
3 years ago
Read 2 more answers
Does anybody watch this anime?
lorasvet [3.4K]

Answer:

no lol.. is this actually for school?

5 0
4 years ago
Read 2 more answers
State the Boyle's Law. If the graph for Boyle's law is straight line through the origin then state the quantity taken along: a)
astraxan [27]

Answer:

(a) X- axis represent (1/P) inverse of pressure

(b) Y-axis represent (V) volume

Explanation:

Boyle's Law States that at constant temperature, the volume of a fixed mass of gas is inversly proportional to its pressure. It can be expressed mathematically as

V α 1/P

VPα1

removing the proportionality sign and introducing a constant

VP = k

V₁P₁ = V₂P₂

Where V₁ and V₂ are initial and final volume respectively, P₁ and P₂ are initial and final pressure respectively.

If the graph for Boyle's law is straight line through the origin,

(a) X-axis represent (1/P) inverse of pressure

(b) Y- axis represent (V) volume.

7 0
3 years ago
a nonrelativistic proton is confined to a length of 2.0 pm on the x-axis. what is the kinetic energy of the proton if its speed
Elina [12.6K]

Answer:

K = 1.29eV

Explanation:

In order to calculate the kinetic energy of the proton you first take into account the uncertainty principle, which is given by:

\Delta x \Delta p\geq \frac{h}{4\pi}      (1)

Δx : uncertainty of position = 2.0pm = 2.0*10^-12m

Δp: uncertainty of momentum = ?

h: Planck's constant = 6.626*10^-34 J.s

You calculate the minimum possible value of Δp from the equation (1):

\Delta p=\frac{h}{4\pi \Delta x}=\frac{6.626*10^{-34}J.s}{4\pi(2.0*10^{-12}m)}\\\\\Delta p=2.63*10^{-23}kg.\frac{m}{s}

The minimum kinetic energy is calculated by using the following formula:

k=\frac{(\Delta p)^2}{2m}       (2)

m: mass of the proton = 1.67*10^{-27}kg

k=\frac{(2.63*10^{-23}kgm/s)^2}{2(1.67*10^{-27}kg)}=2.08*10^{-19}J

in eV you have:

2.08*10^{-19}J*\frac{6.242*10^{18}eV}{1J}=1.29eV

The kinetic energy of the proton is 1.29eV

7 0
3 years ago
Find the net rate of heat transfer by radiation in watts from a skier standing in the shade, given the following. She is complet
fomenos

Answer:

-34.5 W

Explanation:

rate of heat transfer = Stefan-Boltzmann constant x emissivity x surface area x temperature^4

P = \alpha eA(T_{f} ^{4}- T_{i} ^{4}) = 5.67*10^{-8} *0.205*1.5(256^{4} - 284.4^{4} ) = -34.5 W

6 0
3 years ago
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