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sammy [17]
3 years ago
14

A 2.0-kg ball with an initial velocity of (4i + 3j) m/s collides with a wall and rebounds with a velocity of (–4i + 3j) m/s. Wha

t is the impulse exerted on the ball by the wall?
Physics
1 answer:
hichkok12 [17]3 years ago
6 0

Answer:

-16i kgm/s

Explanation:

Impulse I = m(v - u) where m = mass of ball = 2.0 kg, u = initial velocity of ball = (4i + 3j) m/s  and v = final velocity of ball = (-4i + 3j) m/s.

So, the impulse is thus

I = m(v - u)

= 2.0 kg[(-4i + 3j) m/s - (4i + 3j) m/s]

= 2.0 kg[(-4i - 4i) + (3j - 3j) m/s]

= 2.0kg[-8i + 0j] m/s

= -16i kgm/s

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Two sound waves, from two different sources with the same frequency of 420 Hz travel in the same direction at 336 m/s. The sourc
Tresset [83]

Answer:

Pi(3.14) radians or 180º degrees

Explanation:

First of all, we need to obtain the wavelength of a wave traveling to the speed of sound and 420 Hz of frequency.

The formula is:

l=wavevelocity/frequency

where l = wavelength in meters

With current values:

l = 336 [m/s]/420[1/s] = 0.8 meters

Since a complete cycle (360º or 2pi radians) needs 0.8 meters to complete, 0.4 meters or 40 cm is just half of it, making a 180º degree phase or 3.14 radians.

8 0
3 years ago
If its wavelength were doubled, its energy would be If its wavelength were doubled, its energy would be 4E. 2E. 12E. 14E.
ANEK [815]

The wavelength was doubled, and its energy will be increased by 4 times.

looking at the formula

energy E = MC^2

also, c = \lambda \times \nu

hence it is clear from above that energy is directly proportional to the square of the wavelength.

hence, The wavelength was doubled, and its energy will be increased by 4 times.

<h3>What is Wavelength?</h3>
  • The distance over which a periodic wave's shape repeats is known as the wavelength in physics.
  • It is a property of both traveling waves and standing waves as well as other spatial wave patterns. It is the distance between two successive corresponding locations of the same phase on the wave, such as two nearby crests, troughs, or zero crossings.
  • The spatial frequency is the reciprocal of the wavelength. The Greek letter lambda is frequently used to represent wavelength.
  • The term wavelength is occasionally used to describe modulated waves, their sinusoidal envelopes, or waves created by the interference of several sinusoids.

To learn more about wavelength with the given link

brainly.com/question/13533093

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5 0
2 years ago
\Parts of a device that use radio waves. On the left is a box labeled A. On the right is a box labeled B. There is a vector poin
Elodia [21]

The radio waves travels between the two boxes and they were travelling through air,

  • Box B captures, amplifies and demodulates radio waves.
  • Box A modulates, amplifies and send out radio waves.

<h3>What are radio waves?</h3>
  • Radio waves are the type of radiation from the electromagnetic spectrum.
  • The radio waves can be used in communication technologies like computer, phones, radios , etc..
  • Radio waves have lower frequencies but longer wavelength.
  • These devices will get signal and then it transmit as mechanical waves through sound.

In that way, the radio waves from box A to B through air, the box A will gets the signal, and then modulates, amplifies and then it send out radio waves. Through the air, Box B will captures, amplifies and demodulates radio waves.

Learn more about radio waves,

brainly.com/question/13989450

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3 0
2 years ago
Two men each weigh 650 N. One man carries +1.0 C of excess charge, the other −1.0 C of excess charge. How far apart must they be
sergejj [24]

Coulomb's law:

F = k×q₁×q₂/r² where k ≈ 9.00×10⁹NC⁻²m²


Given values:

q₁ = +1.0C

q₂ = -1.0C

F = 650N


Substitute the terms in Coulomb's law with our given values. We will have to use the absolute value of q₂ to so the algebra works out. Solve for r:

650 = 9.00×10⁹×1.0×1.0/r²

r = 3721m

Taking significant figures into account:

<h3>r = 3700m</h3>
6 0
3 years ago
Read 2 more answers
What is the magnitude of the electric field 17.1 cm directly above an isolated 1.83Ã10â5 C charge?
11111nata11111 [884]

Answer:

Electric field, E=5.63\times 10^{16}\ N/C

Explanation:

Given that,

Charge, q=1.83\times 10^5\ C

We need to find the magnitude of electric field 17.1 cm (0.171 m) above an isolated charge. Electric field at a point is given by :

E=\dfrac{kq}{r^2}

E=\dfrac{9\times 10^9\times 1.83\times 10^5\ C}{(0.171\ m)^2}

E=5.63\times 10^{16}\ N/C

So, the electric field is 5.63\times 10^{16}\ N/C. Hence, this is the required solution.

5 0
3 years ago
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