Answer:
Explanation:
mass of bullet, m = 2.5 g
initial velocity of bullet, u = 425 m/s
mass of block, M = 215 g
(a) Let the speed of bullet block system is v
Use the conservation of momentum
m x u + M x 0 = (M + m) x v
2.5 x 425 = ( 215 + 2.5) x v
v = 4.89 m/s
(b) Let it rise upto height h
Use conservation of energy
Kinetic energy after collision = Potential energy
1/2 (M + m) v² = ( M+ m) x gx h
0.5 x 4.89 x 4.89 = 9.8 x h
h = 1.22 m