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3 years ago

Can y’all please help me with the two part question?

Physics

1 answer:

Valentin [98]3 years ago

6 0

Exactly the same situation as the baseball rolling off the desk, only with different numbers.

Distance falling from rest = (1/2) · (g) · (T²)

Janet fell from rest and landed in the water 2.1 sec later.

How high did she fall from ?

Distance = (1/2) · (9.8 m/s²) · (2.1 sec)²

Distance = (4.9 m/s²) · (4.41 s²)

<em>Distance = 21.61 meters</em> (HIGH platform. About 71 feet ! ! )

She didn't just roll off the edge of the platform.

She shot out from it horizontally, at 2.46 m/s.

She kept moving horizontally at 2.46 m/s all the way down.

How far was she from the tower when she went <em>SPLAT</em> at the bottom ?

Distance = (speed) · (time)

Distance = (2.46 m/s) · (2.1 sec)

<em>Distance = 5.17 meters</em>

<em>(That's 17 feet from the tower ! I sure hope they put the pool that far out.)</em>

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Answer:

8.57 Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength (λ) = 3.5 m

Velocity (v) = 30 m/s

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The velocity, wavelength and frequency of a wave are related according to the equation:

Velocity = wavelength × frequency

v = λ × f

With the above formula, we can simply obtain the frequency of the wave as follow:

Wavelength (λ) = 3.5 m

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Frequency (f) =?

v = λ × f

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Divide both side by 3.5

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If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be $V_e = \sqrt{\dfrac{GM}{r}}$ .

<h3>What is an escape velocity?</h3>

The ratio of the object's travel distance over a specific period of time is known as its velocity. As a vector quantity, the velocity requires both the magnitude and the direction. the slowest possible speed at which a body can break out of the gravitational pull of a certain planet or another object.

The formula to calculate the escape velocity of earth is given below:-

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Given that earth's mass was half its actual value but its radius stayed the same. The escape velocity will be calculated as below:-

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$V_e = \sqrt{\dfrac{GM}{r}}$ .

Therefore, If the earth's mass were half its actual value but its radius stayed the same, the escape velocity of the earth would be $V_e = \sqrt{\dfrac{GM}{r}}$ .

To know more about escape velocity follow

brainly.com/question/14042253

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