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3 years ago

Two points are given in polar coordinates by : (r, θ) = (2.60 m, 50.0°)

Physics

1 answer:

alukav5142 [94]3 years ago

5 0

Answer:

The distance between the 2 points is 4.6558 meters.

Explanation:

The distance between 2 points $(r_1,\theta _1),(r_2,\theta _2)$ is given by

$d=\sqrt{r_{1}^{2}+r_{2}^{2}-2r_1\cdot r_2cos(\theta _2-\theta _1)}$

In our case the given 2 points are $(2.60,50.0^{o}),(3.60,-46.0^{o})$ hence the distance is

$d=\sqrt{2.60^{2}+3.60^{2}-2\cdot 2.60\cdot 3.60\cdot cos(-46.0-50)}\\\\\therefore d=4.6558m$

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A circuit is built based on this circuit diagram. What is the equivalent resistance of the circuit?

Dmitry_Shevchenko [17]

The three resistors are connected to the same points of the circuit, so they are in parallel configuration. The equivalent resistance of 3 resistors in parallel is given by:
$\frac{1}{R_{eq}}= \frac{1}{R_1}+ \frac{1}{R_2}+ \frac{1}{R_3}$
If we plug the values of the resistances into the formula, we find
$\frac{1}{R_{eq}}= \frac{1}{3.0 \Omega}+ \frac{1}{6.0 \Omega}+ \frac{1}{9.0 \Omega}= \frac{6+3+2}{18.0 \Omega} = \frac{11}{18.0 \Omega}$
From which we find the equivalent resistance:
$R_{eq} = \frac{18.0}{11} \Omega =1.6 \Omega$

So, the correct answer is B.

7 0

3 years ago

A 300 kg piano needs to be moved to the other side of the room. The maximum static frictional force is equal to 90 N and the kin

riadik2000 [5.3K]

Answer:

a = 0.1 m/s²

Explanation:

If the maximum static frictional force is 90 N, this means that any applied force that will overcome this force, will cause the piano to slide, so kinetic frictional force applies.
Under these conditions, the net force in the horizontal direction is just the difference between the applied force (which is larger that the static friction force) and the kinetic frictional force, as follows:

$F_{net} = F_{app} -F_{frk} = 100 N - 70 N = 30 N (1)$

By the same token, according Newton's 2nd Law, this force is just equal to the product of the mass of the piano, times the acceleration, as follows:

$F_{net} = m* a = 300 Kg * a = 30 N (2)$

Solving for a:

$a = \frac{F_{net}}{m} = \frac{30 N}{300kg} = 0.1 m/s2 (3)$

5 0

3 years ago

A helicopter flies 25 km north, 5 km east, then 5 km S, then 15 km W. What is the resultant displacement and direction of the he

ch4aika [34]

Answer:

Explanation:

Plotting the original location of the helicopter before it flies 25 km north, it would be at the origin, (0,0) then after it flies north, the y vertex gains 25 points, so it would be (0,25)

After it flies east, the x coordinate gains 5 points, so it would now be (5,25)

After it flies south, the y coordinate loses or is subtracted by 5 points. so it would now be (5,20)

After flying west, the x coordinate loses 15 points. So the final vertex would be at (-10,20)

East = Right

West = Left

South= Down

North = Up

I used mainly mathematical methods by adding and subtracting the x and y coordinate values, but this could be graphed easily since I gave the coordinates just incase!

Hope this helps!

7 0

3 years ago

A truck traveled 400 meters north in 80 seconds and then it traveled 300 meters east in 70 seconds. The magnitude of the average

Varvara68 [4.7K]

Answer:

3.3m/s

Explanation:

You first get the total time (80 + 70 = 150s).

Then you would find the displacement of the truck. To do that you would do component method (vector addition), so since its a right triangle (North and East), displacement is 400^2 + 300^2 = d^2.

d= 500m.

So now that you have displacement and time, you can find the velocity:

v=d/t

v=500/150

v=3.3

5 0

3 years ago

How might the changes in tide affect a fishing community?

artcher [175]

Answer:

THEY WOULD FIND DED FISH:)))))

Explanation:

6 0

3 years ago