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liraira [26]
3 years ago
7

Two points are given in polar coordinates by : (r, θ) = (2.60 m, 50.0°)

Physics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

The distance between the 2 points is 4.6558 meters.

Explanation:

The distance between 2 points (r_1,\theta _1),(r_2,\theta _2) is given by

d=\sqrt{r_{1}^{2}+r_{2}^{2}-2r_1\cdot r_2cos(\theta _2-\theta _1)}

In our case the given 2 points are (2.60,50.0^{o}),(3.60,-46.0^{o}) hence the distance is

d=\sqrt{2.60^{2}+3.60^{2}-2\cdot 2.60\cdot 3.60\cdot cos(-46.0-50)}\\\\\therefore d=4.6558m

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If a proton were released in the electric field above, what direction would it move?
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Answer:

d because the proton would move towards the negative plate

Explanation:

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3 years ago
A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If
Salsk061 [2.6K]

Complete question:

A 45-mH ideal inductor is connected in series with a 60-Ω resistor through an ideal 15-V DC power supply and an open switch. If the switch is closed at time t = 0 s, what is the current 7.0 ms later?

Answer:

The current in the circuit 7 ms later is 0.2499 A

Explanation:

Given;

Ideal inductor, L = 45-mH

Resistor, R =  60-Ω

Ideal voltage supply, V = 15-V

Initial current at t = 0 seconds:

I₀ = V/R

I₀  = 15/60 = 0.25 A

Time constant, is given as:

T = L/R

T = (45 x 10⁻³) / (60)

T = 7.5 x 10⁻⁴ s

Change in current with respect to time, is given as;

I(t) = I_o(1-e^{-\frac{t}{T}})

Current in the circuit after 7 ms later:

t = 7 ms = 7 x 10⁻³ s

I(t) = I_o(1-e^{-\frac{t}{T}})\\\\I =0.25(1-e^{-\frac{7*10^{-3}}{7.5*10^{-4}}})\\\\I = 0.25(0.9999)\\\\I = 0.2499 \ A

Therefore, the current in the circuit 7 ms later is 0.2499 A

6 0
3 years ago
1 If you measured the distance travelled by a snail in
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The answer is m/s hope it helps
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2 years ago
Busco<br>n o<br><br><br><br><br>Vi<br><br><br><br><br>oookuflufurlgxbmhxmdhkhdkydkdul​
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Explanation:

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4 0
3 years ago
A ski tow operates on a slope of angle 15.6 ∘ of length 340 m . The rope moves at a speed of 12.7 km/h and provides power for 53
GREYUIT [131]

Answer:

P = 34034.2 Watt

Explanation:

As we know that the slope angle is given as

\theta = 15.6^0

now the weight of the rider along the slope is given as

W = mgsin\theta

W = 69(9.81)sin15.6

W = 182 N

now total weight of all 53 riders along the slope is given as

F = 53 W

F = 9647.5 N

now the speed of the rope is given as

v = 12.7 km/h = 3.53 m/s

now the power required is given as

P = F.v

P = 9647.5(3.53)

P = 34034.2 Watt

3 0
2 years ago
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