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liraira [26]
3 years ago
7

Two points are given in polar coordinates by : (r, θ) = (2.60 m, 50.0°)

Physics
1 answer:
alukav5142 [94]3 years ago
5 0

Answer:

The distance between the 2 points is 4.6558 meters.

Explanation:

The distance between 2 points (r_1,\theta _1),(r_2,\theta _2) is given by

d=\sqrt{r_{1}^{2}+r_{2}^{2}-2r_1\cdot r_2cos(\theta _2-\theta _1)}

In our case the given 2 points are (2.60,50.0^{o}),(3.60,-46.0^{o}) hence the distance is

d=\sqrt{2.60^{2}+3.60^{2}-2\cdot 2.60\cdot 3.60\cdot cos(-46.0-50)}\\\\\therefore d=4.6558m

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A race car traveling at 10 meters per second accelerates at 1.5 meters per second squared while moving a distance of 600 meters.
Mekhanik [1.2K]

Answer:

Explanation:

Givens

vi = 10 m/s

a = 1.5 m/s^2

d = 600 m

vf = ?

Formula

vf^2 = vi^2 + 2*a*d

Solution

vf^2 = 10^2 + 2*1.5 * 600

vf^2 = 100 + 1800

vf^2 = 1900

sqrt(vf^2) = sqrt(1900)

vf = 43.59 m/s

7 0
3 years ago
Which of the following is not an example of a polymer?
Gala2k [10]
Concrete is not a polymer which Nylon, and Kevlar are
8 0
3 years ago
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A blank is any disturbance that carries energy from one place to another through matter and space.
Eduardwww [97]
<h3>Answer;</h3>

<em>A wave </em>

<em><u>A wave</u></em> is any form of a disturbance that carries energy from one place to another through a matter and space

<h3>Explanation;</h3>
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3 years ago
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Convert planks constant in cgs system
dezoksy [38]

in cgs system, plank's constant= h=6.626 x10⁻²⁶ erg s

Value of Plank's constant in SI system= 6.626 x10⁻³⁴ Js

now 1 Joule= 10⁷ ergs

so h= 6.626 x10⁻³⁴ Js (10⁷ ergs/1J)

h=6.626 x10⁻²⁷ erg s

7 0
3 years ago
A 6.3 g bullet leaves the muzzle of a rifle with a speed of 596.2 m/s. what constant force is exerted on the bullet while it is
ivanzaharov [21]
<span>anwser will be 

F = ma

where 

F = force exerted on the bullet 
m = mass of the bullet = 5 gm (given) = 0.005 kg. 
a = acceleration of the bullet 

Substituting appropriately, 

F = 0.005a --- call this Equation 1 

Next working equation is 

Vf^2 - Vo^2 = 2as 

where 

Vf = velocity of the bullet as it leaves the muzzle = 326 m/sec (given) 
Vo = initial velocity of bullet = 0 
a = acceleration of bullet 
s = length of the rifle's barrel 

Substituting appropriately, 

326^2 - 0 = 2(a)(0.83) 

a = 64,022 m/sec^2 

the anwser will be
Substituting this into Equation 1, 

F = 0.005(64,022) 

F =320.11 Newtons 

Hope this helps. </span><span>
</span>
8 0
3 years ago
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