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2 years ago

14

Determine if the following equations are balanced or unbalanced

1 answer:

jeka57 [31]2 years ago

7 0

Eis your answer to the question

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Express the following numbers as decimals: (a) 1.52 x 10^-2, (b) 7.78 x 10^-8, (c) 1 x 10^-6, (d) 1.6001 x 10^3.

Alchen [17]

Answer :

(a) 0.0152

(b) 0.0000000778

(c) 0.000001

(d) 1600.1

Explanation :

Scientific notation : It is the representation of expressing the numbers that are too big or too small and are represented in the decimal form with one digit before the decimal point times 10 raise to the power.

For example :

5000 is written as $5.0\times 10^3$

889.9 is written as $8.899\times 10^{-2}$

In this examples, 5000 and 889.9 are written in the standard notation and $5.0\times 10^3$ and $8.899\times 10^{-2}$ are written in the scientific notation.

(a) $1.52\times 10^{-2}$

The standard notation is, 0.0152

(b) $7.78\times 10^{-8}$

The standard notation is, 0.0000000778

(c) $1\times 10^{-6}$

The standard notation is, 0.000001

(d) $1.6001\times 10^{3}$

The standard notation is, 1600.1

5 0

3 years ago

What is the mass number of lithium isotope that consists of 3 protons, 4 neutron and 3 electrons

sweet-ann [11.9K]

Answer:

7. ok

please mark me brainlistb

6 0

2 years ago

777 Joules of energy are applied to 25.0 grams of each of the following materials, which

4vir4ik [10]

Answer:

I think copper

Explanation:

Material IACS % Conductivity

Silver 105

Copper 100

Gold 70

Aluminum 61

Nickel 22

Zinc 27

Brass 28

Iron 17

Tin 15

Phosphor Bronze 15

Lead 7

Nickel Aluminum Bronze 7

Steel 3 to 15

the table might help- your indian brother

3 0

2 years ago

A gas mixture with 4 mol of Ar, x moles of Ne, and y moles

maks197457 [2]

Answer:

a) $\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

b) $x=4$

c) $\Delta G_{max}=-2721.9 J/mol$

Explanation:

Gas mixture:

$n_{Ar}= 4 mol$

$n_{Ne}= x mol$

$n_{Xe}= y mol$

$n_{tot}= n_{Ar} + n_{Ne} + n_{Xe}=3*n_{Ar}$

$n_{Ne} + n_{Xe}=2*n_{Ar}$

$x + y=8 mol$

$y=8 mol- x$

Mol fractions:

$x_{Ar}=\frac{4 mol}{12 mol}=1/3$

$x_{Ne}=\frac{x mol}{12 mol}=x/12$

$x_{Xe}=\frac{8 - x mol}{12 mol}=(8-x)/12$

Expression of $\Delta G_{mixing}$

$\Delta G_{mixing}=R*T*\sum_{i]*x_i*ln (x_i)$

$\Delta G_{mixing}=R*T*[1/3*ln (1/3) +x/12*ln (x/12) +(8-x)/12*ln ((8-x)/12)]$

$\Delta G_{mixing}=\frac{R*T}{12}*[4*ln (1/3) +x*ln (x/12) +(8-x)*ln ((8-x)/12)]$

Expression of $\Delta G_{max}$

$\frac{d \Delta G_{mixing}}{dx}=0$

$\frac{d \Delta G_{mixing}}{dx}=\frac{R*T}{12}*[ln (x/12)+12-ln ((8-x)/12)-12]$

$0=\frac{R*T}{12}*[ln (x/12)-ln ((8-x)/12)$

$0=[ln (x/12)-ln ((8-x)/12)$

$ln (x/12)=ln ((8-x)/12)$

$x=(8-x)$

$x=4$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (4/12) +(8-4)*ln ((8-4)/12)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[4*ln (1/3) +4*ln (1/3) +(4)*ln (1/3)]$

$\Delta G_{max}=\frac{8.314*298}{12}*[12*ln (1/3)]$

$\Delta G_{max}=-2721.9 J/mol$

4 0

3 years ago

Need help with question

3241004551 [841]

C, because a homogeneous mixture is evenly mixed.

All those others would be heterogeneous (not evenly mixed).

5 0

3 years ago

Read 2 more answers