Determine if the following equations are balanced or unbalanced

Need answer ASAP!! The specific heat capacity of metal A is twice that of metal B. Based on

AURORKA [14]

Answer:

last choice

Explanation:

Specific heat of a metal is j/kg-c

It says nothing about melting point or heat of fusion

A = twice B = 2 * j/kg-c B = j/kg-c

if j is constant and mass is the same we can write this more like

A = 2 /C and B = 1/C

or A ~ C/2 and B~ C

now you can see that the temp change in A will be 1/2 that of B

4 0

2 years ago

What do kinetic and potential energy have in common

adell [148]

Just simply... they both are energy.
Use a bow and arrow as an example:
When you pull back an arrow, potential energy or PE is stored in the string and the limbs of the bow.
When you release the the arrow, energy is being transferred from the bow to the arrow. The arrow now has kinetic energy or KE, this means that the energy is being used by the arrow.

7 0

3 years ago

In the energy diagram, which number represents the potential energy of the products?

Lesechka [4]

I say Answer choice A because it is a straight line and it hasn't gone under all those reactions yet.

6 0

3 years ago

Read 2 more answers

Measurements show that the enthalpy of a mixture of gaseous reactants increases by 215. kJ during a certain chemical reaction, w

Maslowich

Answer:

1. The change in energy is 60KJ or 6.0 × 10^1 KJ

2. Endothermic reaction

Explanation:

The Enthalpy (ΔU) for the mixture is given as 215kJ and the workdone (W) on the mixture is - 155KJ. Hence, the change in the energy (ΔH) ofthe mixture is computed using the equation below:

ΔH = ΔU + w

Where,

ΔH= Change in energy

ΔU= Enthalpy change

W= workdone

Therefore ΔH is:

ΔH= 215 kJ + (-155Kj)

ΔH= 60 KJ

Therefore, the change in energy is 60KJ or 6.0 × 10^1 KJ

The value is positive so it is an endothermic reaction.

An endothermic reaction happens when the energy used to break the bonds in the reactants is higher than the energy given out when bonds are formed in the products. This means that the entire reaction takes in energy, hence there is a temperature decrease in the surroundings. Endothermic reactions cannot happen spontaneously. Work is usually done in order to get these reactions to occur. When endothermic reactions absorb energy, a temperature drop is measured by the reaction.

6 0

3 years ago

Glucose (C6H12O6) is a key nutrient for generating chemical potential energy in biological systems. We were provided 16.55 g of

harina [27]

Answer:

a) 40 %

b) $4.04~g~CO_2$

c) $5.53x10^2^3~molecules~of~O_2$

Explanation:

For a) we will have to calculate the molar mass of $C_6H_1_2O_6$ , so the first step is to find the atomic mass of each atom and multiply by the amount of atoms in the molecule.

C => 12*(6) = 72

H => 1*(12) = 12

O => 6*(16) = 96

Molar mass = 180 g/mol

Then we can calculate the percentage by mass:

$Percentage~=~\frac{72}{180}*100=40$

For b) we have to start with the reaction of glucose:

$C_6H_1_2O_6~+~6O_2~->~6CO_2~+~6H_2O$

Then we have to convert the grams of glucose to moles, the moles of glucose to moles of carbon dioxide and finally the moles of carbon dioxide to grams. To do this we have to take into account the following conversion ratios:

-) 180 g of glucose = 1 mol glucose

-) 1 mol glucose = 6 mol carbon dioxide

-) 1 mol carbon dioxide = 44 g carbon dioxide

$16.55~g~C_6H_1_2O_6\frac{1~mol~C_6H_1_2O_6}{180~g~C_6H_1_2O_6}\frac{6~mol~CO_2}{1~mol~C_6H_1_2O_6}\frac{44~g~CO_2}{1~mol~CO_2}=4.04~g~CO_2$

For C, we have to start with the conversion from grams of glucose to moles, the moles of glucose to moles of oxygen and finally the moles of oxygen to molecules. To do this we have to take into account the following conversion ratios:

-) 180 g of glucose = 1 mol glucose

-) 1 mol glucose = 6 mol oxygen

-) 1 mol oxygen = 6.023x10^23 molecules of O2

$16.55~g~C_6H_1_2O_6\frac{1~mol~C_6H_1_2O_6}{180~g~C_6H_1_2O_6}\frac{6~mol~O_2}{1~mol~C_6H_1_2O_6}\frac{6.023x10^2^3~molecules~O_2}{1~mol~O_2}=~5.53x10^2^3~molecules~of~O_2$

4 0

3 years ago