Answer: Force on a current-carrying wire
F = I L x B
where F, L and B are all vectors, x means cross product.
I = 0.410 A
L = (0.689, 0, 0) m
B = (0, 0.000330, 0.0110) T
F = 0.410*(0.689, 0, 0) x (0, 0.000330, 0.0110) N
= (0, -0.410*0.689*0.0110, 0.410*0.689*0.000330)
= (0, -3.11*10^-3, 9.32*10^-5) N
so
a) Fx = 0
b) Fy = -3.11*10^-3 N
c) Fz = 9.32*10^-5 N
32
Explanation: make me brainlyest please i really need it please
