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xxMikexx [17]
3 years ago
5

A wire 43.7 cm long carries a 0.450 A current in the positive direction of an x axis through a magnetic field with an x componen

t of zero, a y component of 0.000360 T, and a z component of 0.00830 T. Find the (a) x, (b) y, and (c) z components of the magnetic force on the wire.
Physics
1 answer:
zubka84 [21]3 years ago
3 0

Answer: Force on a current-carrying wire

F = I L x B

where F, L and B are all vectors, x means cross product.

I = 0.410 A

L = (0.689, 0, 0) m

B = (0, 0.000330, 0.0110) T

F = 0.410*(0.689, 0, 0) x (0, 0.000330, 0.0110) N

= (0, -0.410*0.689*0.0110, 0.410*0.689*0.000330)

= (0, -3.11*10^-3, 9.32*10^-5) N

so

a) Fx = 0

b) Fy = -3.11*10^-3 N

c) Fz = 9.32*10^-5 N

32

Explanation: make me brainlyest please i really need it please

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the object has negative acceleration and eventually

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At distances greater than 2 femtometers, the nuclear strong force is stronger than (select all that apply):
grigory [225]
The correct answer is
<span>nuclear weak force
</span><span>
In fact, the nuclear strong force has a very limited range of action (approximately below 1-2 femtometers), and its magnitude decays exponentially for larger distances. Only the nuclear weak force is weaker than the nuclear strong force at large distance, while the gravity and the electromagnetic force become dominant for distances > 2 femtometers.</span>
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Which of the following statements about atoms is true?
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6 0
4 years ago
a merry go round has a radius of 8 meters makes 2 revolutions every 2.5 minutes. A. express the angular speed of the merry go ar
pantera1 [17]

Answer:

a).v=83.77x10^{-3} rad/s

b).v=0.8rpm

c).v=0.5865 m/sec.

Explanation:

Given:

r=8m

v=\frac{2rev}{2.5minutes}

a).

2 rev*\frac{2\pirad}{1rev}=4\pi  rad

t=2.5minutes*\frac{60s}{1minute}=150s

The angular speed in radians per seconds is

v=\frac{4\pi}{150s}=83.77x10^{-3} rad/s

b).

v=\frac{2rev}{2.5minute}rpm

v=0.8rpm

c)

Child's distance per revolution

(pi*2r) = 43.988 metres.  

v=(43.988 x 0.0133333) = 0.5865 m/sec.

4 0
3 years ago
A baseball approaches home plate at a speed of 44.0 m/s, moving horizontally just before being hit by a bat. The batter hits a p
Luda [366]

Explanation:

It is given that,

Speed of the baseball, u = 44 m/s

Speed of the baseball, v = 53 m/s

Mass of the ball, m = 145 g = 0.145 kg

Time of contact between the ball and the bat, t = 2.2 ms = 0.0022 s

F=ma

F=\dfrac{mv}{t}

F_1=\dfrac{0.145\ kg\times 44\ m/s}{0.0022\ s}

F₁ = 2900 N...........(1)

F=ma

F=\dfrac{mv}{t}

F_2=\dfrac{0.145\ kg\times 53\ m/s}{0.0022\ s}

F₂ = 3493.18 N.........(2)

In average vector form force is given by :

F=F_1+F_2

F=(2900i+(-3493.18)\ N

F=(2900i-3493.18j)\ N

Hence, this is the required solution.

6 0
4 years ago
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