Answer:
D. Top is emission; bottom absorption.
Explanation:
Emission and spectrum of elements are due to the element absorbing or emitting wavelength of e-m energy. Elementary particles of elements can absorb energy from a ground state to enter an excited state, creating an absorption spectrum, or they can lose energy and fall back to a lower energy state, creating an emission spectrum. A simple rule to differentiate between an emission and an absorption spectrum is that: "all absorbed wavelength is emitted, but not all emitted wavelength is absorbed."
From the image, the lines indicates wavelengths. We can see that all of the wavelengths of the bottom absorption spectrum coincides with some of the wavelength of the upper emission wavelengths.
1) Impulse:
2) Strong force: -131.1 N, weak force: -44.7 N
Explanation:
1)
The impulse exerted on an object is equal to the change in momentum of the object itself.
Mathematically:
where
m is the mass of the object
u is the initial velocity
v is the final velocity
For the skateboarder in this problem, we have:
m = 53.6 kg
u = 4.45 m/s
v = 0 (it comes to a stop)
Therefore, the impulse is
Where the negative sign indicates that the direction is opposite to the motion of the object.
2)
The impulse is also equal to the product between the force applied and the duration of the collision:
where
I is the impulse
F is the average force
is the time during which the force is applied
The strong force is applied in a time of
Therefore this force is
The weak force is applied in a time of
So this force is
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The net speed due west is = distance traveled in west / time taken = 120/0.5 = 240 km/h.
so airspeed due west is = net speed - speed of plane = 240-220= 20 km/h.
airspeed due south is = distance traveled in west / time taken= 20/0.5= 40 km/h.
the magnitude of the wind velocity = √[(airspeed due south )² + (airspeed due west)²] = √ ( 40^2 + 20^2 ) = 44.72 km/h
the angle of airspeed south of west is tan⁻¹ ( airspeed due south / airspeed due west )= tan⁻¹(40/20)=63.43 degrees.
if wind velocity is 40 km/h due south, her velocity should have 20 km/h component in north.
so component west = sqrt ( 220^2 - 40^2 ) = 216.33 km/h.
the angle north of west is arctan( 40/216.33 ) = 10.47 degrees.
Answer:
The energy stored in the capacitor quadruples its original value.
Explanation:
The energy stored in a capacitor is given by the equation
where
C is the capacitance
V is the voltage across the plates
The capacitance, C, depends only on the properties of the capacitor, so it does not change when the voltage applied is changed.
Instead, in this problem the voltage applied is doubled:
V' = 2V
So the new energy stored is
so, the energy stored has quadrupled.