From the calculation, the pH of the solution after dilution is 3.
<h3>What is the pH?</h3>
The pH is the hydrogen ion concentration of the solution. Now we know that;
C1 = 0.010 m
V1 = 10.0 ml
V2 = 10.0 ml + 100.0 ml = 110 ml
C2 = ?
C1V1 = C2V2
C2 = C1V1 /V2
C2 = 0.010 m * 10.0 ml / 110 ml
C2 = 0.00091 M
pH = -log[0.00091 M]
pH = 3
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Answer:
45.95 Jkg^-1°C^-1
Explanation:
as specific heat capacity = heat energy / mass × delta
temperature
=52500/10.2×112
=45.95 Jkg^-1°C^-1
Answer:
23.8 L
Explanation:
There is some info missing. I think this is the original question.
<em>Calculate the volume in liters of a 0.0380M potassium iodide solution that contains 150 g of potassium iodide. Be sure your answer has the correct number of significant digits.</em>
<em />
The molar mass of potassium iodide is 166.00 g/mol. The moles corresponding to 150 grams are:
150 g × (1 mol/166.00 g) = 0.904 mol
0.904 moles of potassium iodide are contained in an unknown volume of a 0.0380 mol/L potassium iodide solution. The volume is:
0.904 mol × (1 L/0.0380 mol) = 23.8 L
