Answer:
The correct answer is - 29.45 / 100 x 25.6 = 7.5392 grams
Explanation:
It is given in the question that in 100 gms of CaSO4 there are 29.45 grams of Ca present and there is 25.6 gram of total CaSO4 sample present, So, to calculate the exact value of calcium in this given sample is:
mass of Ca = total amount of sample*percentage of calcium in sample /100
M of Ca =25.6*29.45/100
M of Ca = 7.5392 grams
Thus, the correct procedure is given by 29.45 / 100 x 25.6 = 7.5392 grams
Answer:
CCl2=CCl2
Explanation:
Recall that the individual dipole moments in a symmetrical molecule cancel out each other thereby making the overall molecule to be non polar.
CCl2=CCl2 contain individual polar bonds but the molecule is highly symmetrical thus its dipole cancel out and the molecule has no overall dipole moment, hence CCl2=CCl2 has a dipole moment of zero .
Answer:
2.4
⋅
10
24
Explanation:
All that you need to know here is that in order for a given sample of water to contain exactly 1 mole of water, it must contain 6.022
⋅
10
23 molecules of water.
This is known as Avogadro's constant and essentially acts as the definition of a mole. If you have 6.022
⋅
10
23 molecules of water, then you can say for a fact that you have 1 mole of water.
1. you need a periodic table and find the atomic mass of Cu (copper), S (sulfur) and O (oxygen). The atomic mass is the number in the box that corresponds to the element and have several decimal places.
2. atomic mass of
Cu = 63.546
S = 32.065
O = 15.9994
3. Then according to the formula of the compound, you add as many time the atomic mass of each element as subindex in the formula and add all the values together to calculate the molecular mass of the compound in grams.
4. 63.546 g + 32.065 g + ( 4 x <span>15.9994) = 159.609 g
5. this value </span><span>159.609 g is the mass in grams of one mol of CuSO4
6 the problem is asking not for the mass of one mole but the mass of 3.65 moles of CuSO4
7 then you have the multiply the value of one mol by the number of moles that the problem is asking you
8. </span><span>159.609 g x 3.65 = 582.571 g
</span>
9 the answer to the problem will be
"there are 582.571 g of CuSO4 in 3.65 moles of CuSO4"
