Answer:
C) 1.3 mol
Explanation:
Using gas law we can find the initial moles of the sample of the mixture, as follows:
PV = nRT
PV / RT = n
<em>Where P is pressure: 4.0atm</em>
<em>V is volume: 9.6L</em>
<em>R is gas constant: 0.082atmL/molK</em>
<em>T is absolute temperature: 300K</em>
<em>And n are moles of the gas</em>
<em />
PV / RT = n
4.0atm*9.6L / 0.082atmL/molK300K = n
n = 1.56moles of the mixture of the gas are present into the 9.6L container
Now, 14% of this gas is hydrogen that was removed of the system, that is:
1.56mol*14% = 0.22 moles of hydrogen are removed.
Thus, moles of gas that remains in the container are:
1.56mol - 0.22mol = 1.34mol.
Right answer is:
<h3>C) 1.3 mol</h3>
