Answer:
12.29 M
Explanation:
- The reaction that takes place is:
H₂SO₄ + 2NaOH → 2Na⁺ + SO₄⁻² + 2H₂O
- Now let's calculate the <u>moles of H₂SO₄ that were titrated</u>:
= 0.01229 mol H₂SO₄.
- Thus, the <u>concentration of the diluted solution is</u>:
0.01229 mol H₂SO₄ / 0.010 L = 1.229 M
- Finally, the <u>concentration of the original acid solution is:</u>
= 12.29 M
Answer:
0.479 M or mol/L
Explanation:
So Molarity is moles/litres of solution...often written as M=mol/L
So here we are given grams of BaCl2 which we have to convert to moles. To convert to moles of BaCl2 we have to divide 63.2 g BaCl2 by molar mass of BaCl2 which is 208.23 g/mol so you get 63.2/208.23 = 0.3035 moles of BaCl2
Second step is converting the 634mL to litres by simply dividing by 1000 because we know 1 litre has 1000ml so 634/1000 = 0.634L
Now we just plug these guys in our molarity formula M=mol/L
M= 0.3035/0.634 = 0.479 M or mol/L
B is the correct answer to your question
Largest to smallest: barium, calcium, selenium, oxygen
<span>
Correct Answer: <u>Option B i.e. 0.82 M
</u>
Reason:
<em>Given:</em> number of moles of BaCl2 = 0.98, Volume of solution = 1.2 l
Molarity of solution = </span>
<span>
= </span>
<span>
= 0.82 M
Thus, molarity of the solution is 0.82 M</span>
