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scZoUnD [109]
3 years ago
5

Differentiate between acids and bases on the basis of their pH values. Give an example of each type.

Chemistry
1 answer:
Andrews [41]3 years ago
5 0

Bases are the chemical opposite of acids. Acids are defined as compounds that donate a hydrogen ion (H+) to another compound.

Definition of Acids - An acid is any chemical compound which when dissolved in water gives a solution with a hydrogen ion activity greater than in pure water. Bronstead Lowry

Definition of Base - A base is an aqueous substance that can accept hydrogen ions. Bronstead Lowry Definition: A base is any substance which accepts a proton.

Physical Characteristics of Acids - Depending on the temperature, acids can occur in solid, liquid or gaseous form. Taste sour.

Physical Characteristics of Base - Bases feel slippery because of the reaction of the base with the oils of your hand. Frequently solids except ammonia which is a gas. Taste bitter.

Properties of Acids - Electrolytes, conduct electricity (because electrolytes), react with many metals.

Properties of Base - Electrolytes, conduct electricity, ranges from insoluble to so soluble that they can react with water vapor.

Acids are often used to remove rust from metals, as an electrolyte in batteries, for mineral processing, to produce fertilizers and gasoline and as additives in food and beverages. Bases are used primarily in cleaning as dishwashing and laundry detergents, oven cleaners and stain removers.

Here are some differences! Hope this helps, sorry I couldn't think of anything else. ;(

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1.54x10-1 L / 2.36x 10-45 solve this in scientific notation
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3 years ago
Calculate [H3O+] and [OH−] for each of the following solutions at 25 ∘C given the pH. pH= 8.74, pH= 11.38, pH= 2.81
Gnom [1K]

Answer:

Explanation:

Given parameters;

pH  = 8.74

pH = 11.38

pH = 2.81

Unknown:

concentration of hydrogen ion and hydroxyl ion for each solution = ?

Solution

The pH of any solution is a convenient scale for measuring the hydrogen ion concentration of any solution.

It is graduated from 1 to 14

      pH = -log[H₃O⁺]

      pOH = -log[OH⁻]

 pH + pOH = 14

Now let us solve;

   pH = 8.74

             since  pH = -log[H₃O⁺]

                           8.74 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{8.74}

                             [H₃O⁺]  = 1.82 x 10⁻⁹mol dm³

       pH + pOH = 14

                 pOH = 14 - 8.74

                  pOH = 5.26

                  pOH = -log[OH⁻]

                     5.26  = -log[OH⁻]

                     [OH⁻] = 10^{-5.26}

                      [OH⁻] = 5.5 x 10⁻⁶mol dm³

2.  pH = 11.38

             since  pH = -log[H₃O⁺]

                           11.38 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{11.38}

                             [H₃O⁺]  = 4.17 x 10⁻¹² mol dm³

           pH + pOH = 14

                 pOH = 14 - 11.38

                  pOH = 2.62

                  pOH = -log[OH⁻]

                     2.62  = -log[OH⁻]

                     [OH⁻] = 10^{-2.62}

                      [OH⁻] =2.4 x 10⁻³mol dm³

3. pH = 2.81

             since  pH = -log[H₃O⁺]

                           2.81 =  -log[H₃O⁺]

                           [H₃O⁺] = 10⁻^{2.81}

                             [H₃O⁺]  = 1.55 x 10⁻³ mol dm³

           pH + pOH = 14

                 pOH = 14 - 2.81

                  pOH = 11.19

                  pOH = -log[OH⁻]

                     11.19  = -log[OH⁻]

                     [OH⁻] = 10^{-11.19}

                      [OH⁻] =6.46 x 10⁻¹²mol dm³

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Answer:
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Explanation:
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