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dedylja [7]
3 years ago
9

Why do solids maintain their volume and shape? cause-effect

Chemistry
2 answers:
SpyIntel [72]3 years ago
3 0

B.)because they are packet tight

babunello [35]3 years ago
3 0

Answer:

Because they are packet tight.

Explanation:

Solids maintain their volume and shape because they are packet tight.

  • A solid's particles fit closely together.
  • The forces between the particles are so strong that the particles can not move freely; they can only vibrate.
  • This causes a solid to be a stable, non-compressible shape with definite volume.
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erma4kov [3.2K]

Answer:

can u retake the photo it does not show it all?

7 0
3 years ago
Read 2 more answers
How much radium-226 will remain from a 20 gram sample after 4800 years?
ra1l [238]

Answer:

2.5 g mass of Ra-226 will remain after 4800 years.

Explanation:

Given data:

Mass of Ra-226 = 20 g

Sample remain after 4800 years = ?

Solution:

Half life of Ra-226 = 1600 years

Number of half lives passed = T elapsed / half life

Number of half lives passed = 4800 year / 1600 year

Number of half lives passed = 3

At time zero = 20 g

At first half life = 20 g/2 = 10 g

At 2nd half life = 10 g/2 = 5 g

At 3rd half life = 5 g/2 = 2.5 g

Thus, 2.5 g mass of Ra-226 will remain after 4800 years.

4 0
3 years ago
Creatinine, , is a by-product of muscle metabolism, and creatinine levels in the body are known to be a fairly reliable indicato
kherson [118]

Answer:

Molality = 0.0862 mole/kg

Explanation:

Molality = (number of moles of solute)/(mass of solvent in kg)

Number of moles of solute = (mass of Creatinine in the blood sample)/(Molar mass of Creatinine)

To obtain the mass of creatinine in 10 mL of blood. We're told that 1 mg of Creatinine is contained in 1 decilitre of blood.

1 decilitre = 100 mL

1 mg of Creatinine is contained in 100 mL of blood

x mg of Creatinine is contained in 10 mL of blood.

x = (1×10/100) = 0.1 mg = 0.0001 g

Molar mass of Creatinine (C₄H₇N₃O) = 113.12 g/mol

Number of moles of Creatinine in the 10 mL blood sample = (0.0001/113.12) = 0.000000884 moles

Mass of 10 mL of blood = density × volume = 1.025 × 10 = 10.25 mg = 0.01025 g = 0.00001025 kg

Molality of normal creatinine level in a 10.0-ml blood sample = (0.000000884/0.00001025)

Molality = 0.0862 moles of Creatinine per kg of blood.

Hope this Helps!!!

7 0
3 years ago
Ch 8 Test
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4 0
3 years ago
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Even at high T, the formation of NO is not favored:
Readme [11.4K]

Answer:

3,16x10⁻³M

Explanation:

For the reaction:

N₂(g) + O₂(g) ⇄ 2NO(g). The kc is defined as:

kc = [NO]² / [N₂] [O₂] = 4,10x10⁻⁴ <em>(1)</em>

If you add in a 1,0L container 0,25 mol of N₂ and 0,10 mol of O₂, concentrations in equilibrium will be:

[N₂] = 0,25M - x

[O₂] = 0,10M - x

[NO] = 2x

Replacing in (1):

[2X]² / [0,25-x] [0,10-x] = 4,10x10⁻⁴

[2X]² / 0,025 - 0,35x + x²= 4,10x10⁻⁴

4X² = 4,10x10⁻⁴x² - 1,435x10⁻⁴x + 1,025x10⁻⁵

3,99959x² + 1,435x10⁻⁴x - 1,025x10⁻⁵ = 0

Solving for x:

x = -0,0016 (<em>Wrong answer, there is no negative concentrations</em>)

x = 0,00158 (<em>Right answer</em>)

As molar concentration of NO in equilibrium is 2x:

[NO] = 2x = 2×0,00158 = <em>3,16x10⁻³M</em>

I hope it helps!

6 0
4 years ago
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