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dedylja [7]
2 years ago
9

Why do solids maintain their volume and shape? cause-effect

Chemistry
2 answers:
SpyIntel [72]2 years ago
3 0

B.)because they are packet tight

babunello [35]2 years ago
3 0

Answer:

Because they are packet tight.

Explanation:

Solids maintain their volume and shape because they are packet tight.

  • A solid's particles fit closely together.
  • The forces between the particles are so strong that the particles can not move freely; they can only vibrate.
  • This causes a solid to be a stable, non-compressible shape with definite volume.
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Name of the the following unsaturated Hydrocarbon​
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honestly, who knows. I just want to take a s.h.t.t right now.

8 0
3 years ago
Moles /Number of Particles Con
Olin [163]

(2.03x10^22)/(6.02x10^23) = .033721 mol Li

I hope this helps, if not, i am sorry

7 0
2 years ago
What is the molarity of a solution that is prepared by adding 57.1 g of toluene (c 7 ​ h 8 ​ ) (density = 0.867 g/ml) to a 250 m
Virty [35]

Answer:

2.48 mol/L.

Explanation:

  • The molarity of the solution can be expressed as <em>the number of moles of solute in 1.0 liter of the solution, </em>(M = n / V).
  • It is also can be calculated from the relation:

<em>M = (mass / molar mass) solute x (1000 / V of solution)</em>

The solute is toluene and the solvent is benzene.

mass of toluene (solute) = 57.1 g,

molar mass of toluene (solute) = 92.14 g/mol.

volume of the solution = 250 ml.

∴ M =  (mass / molar mass) solute x (1000 / V of solution) = [(57.1 g / 92.14 g/mol) x (1000 / 250 ml)] = 2.48 mol/L.

4 0
3 years ago
Which statement correctly describes diamond and graphite, which are different forms of solid carbon?
mart [117]
They differ in their molecular structures and properties.
5 0
3 years ago
Read 2 more answers
You have 50 ml of a complex mixture of weak acids that contains some HF (pKa = 3.18) and some HCN (pKa = 9.21). Which is larger,
bonufazy [111]

Answer:

\frac{[F^{-}]}{[HF]} is larger

Explanation:

pK_{a}=-logK_{a} , where K_{a} is the acid dissociation constant.

For a monoprotic acid e.g. HA, K_{a}=\frac{[H^{+}][A^{-}]}{[HA]} and \frac{[A^{-}]}{[HA]}=\frac{K_{a}}{[H^{+}]}

So, clearly, higher the K_{a} value , lower will the the pK_{a}

In this mixture, at equilibrium, [H^{+}] will be constant.

K_{a} of HF is grater than K_{a} of HCN

Hence, (\frac{F^{-}}{[HF]}=\frac{K_{a}(HF)}{[H^{+}]})>(\frac{CN^{-}}{[HCN]}=\frac{K_{a}(HCN)}{[H^{+}]})

So, \frac{[F^{-}]}{[HF]} is larger

5 0
3 years ago
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