3 years ago

Which example best demonstrates the process of conduction?

Physics

1 answer:

MrRissso [65]3 years ago

8 0

C/ metal spon gets wa

You might be interested in

We think of our muscular system as the system that helps us move around. It also functions on an internal level by helping food

trapecia [35]

Stomach;small intenstines

7 0

3 years ago

What happens when the objects submerged in a fluid at rest?

Talja [164]

It will act upon a buoyant force on the magnitude of which is equal to weight of the fluid

3 0

3 years ago

A Cessna 150 aircraft has a lift-off speed of approximately 125 km/h. What minimum constant acceleration does this require if th

aivan3 [116]

Answer:

Part a)

$a = 3.65 m/s^2$

Part b)

$t = 9.5 s$

Part c)

$v_f = 55.1 m/s$

Explanation:

Part a)

As we know that it starts from rest and moves on runway by total distance 165 m

so we will have

$v_f^2 - v_i^2 = 2ad$

$v_f^2 - 0 = 2(a)(165)$

$v_f = 125 km/h = 34.7 m/s$

now we have

$a = 3.65 m/s^2$

Part b)

Now for take off time we will have

$v_f - v_i = at$

$34.7 - 0 = 3.65 t$

$t = 9.5 s$

Part c)

$v_f = v_i + at$

$v_f = 0 + (3.65)(15.1)$

$v_f = 55.1 m/s$

7 0

3 years ago

A lens of focal length 15.0 cm is held 10.0 cm from a page (the object ). Find the magnification .

nevsk [136]

Answer:

Magnification, m = 3

Explanation:

It is given that,

Focal length of the lens, f = 15 cm

Object distance, u = -10 cm

Lens formula :

$\dfrac{1}{v}-\dfrac{1}{u}=\dfrac{1}{f}$

v is image distance

$\dfrac{1}{v}=\dfrac{1}{f}+\dfrac{1}{u}\\\\\dfrac{1}{v}=\dfrac{1}{15}+\dfrac{1}{(-10)}\\\\v=-30\ cm$

Magnification,

$m=\dfrac{v}{u}\\\\m=\dfrac{-30}{10}\\\\m=3$

So, the magnification of the lens is 3.

3 0

3 years ago

What exercise will strengthen your legs?

Olin [163]

Answer: Squats and leg lifts

Explanation:

They strengthen your legs!

7 0

3 years ago