<u>Answer:</u> The work done on the object is 110 W
<u>Explanation:</u>
Work is defined as the force that is causing the movement or displacement of an object.
Mathematically,
where,
W = work done on the object
F = Force applied on the object = 55 N
d = displacement = 10 m
Putting values in above equation, we get:
Hence, the work done on the object is 110 W
Answer:
The mass of the wheel is 2159.045 kg
Explanation:
Given:
Radius
m
Force N
Angular acceleration
From the formula of torque,
Γ (1)
Γ (2)
Find momentum of inertia from above equation,
Find the momentum inertia of disk,
Kg
Therefore, the mass of the wheel is 2159.045 kg
Answer:
a)n= 3.125 x electrons.
b)J= 1.515 x A/m²
c) =1.114 x
m/s
d) see explanation
Explanation:
Current 'I' = 5A =>5C/s
diameter 'd'= 2.05 x m
radius 'r' = d/2 => 1.025 x m
no. of electrons 'n'= 8.5 x
a) the amount of electrons pass through the light bulb each second can be determined by:
I= Q/t
Q= I x t => 5 x 1
Q= 5C
As we know that: Q= ne
where e is the charge of electron i.e 1.6 x C
n= Q/e => 5/ 1.6 x
n= 3.125 x electrons.
b) the current density 'J' in the wire is given by
J= I/A => I/πr²
J= 5 / (3.14 x (1.025x )²)
J= 1.515 x A/m²
c) The typical speed'' of an electron is given by:
=
=1.515 x / 8.5 x
x |-1.6 x
|
=1.114 x
m/s
d) According to these equations,
J= I/A
=
=
If you were to use wire of twice the diameter, the current density and drift speed will change
Increase in the diameter increase the cross sectional area and decreases the current density as it has inverse relation.
Also drift velocity will decrease as it is inversely proportional to the area