Using the speed - distance relationship, the time left before the appointed time is 27 minutes.
<u>Recall</u><u> </u><u>:</u>
<u>At</u><u> </u><u>10mph</u><u> </u><u>:</u>
- Distance = 10 × (t + 3) = 10t + 30 - - - (1)
<u>At</u><u> </u><u>12</u><u> </u><u>mph</u><u> </u><u>:</u>
- Distance = 12 × (t - 2) = 12t - 24 - - - - (2)
<em>Equate</em><em> </em><em>(</em><em>1</em><em>)</em><em> </em><em>and</em><em> </em><em>(</em><em>2</em><em>)</em><em> </em><em>:</em>
10t + 30 = 12t - 24
<em>Collect</em><em> </em><em>like</em><em> </em><em>terms</em><em> </em>
10t - 12t = - 24 - 30
-2t = - 54
<em>Divide</em><em> </em><em>both</em><em> </em><em>sides</em><em> </em><em>by</em><em> </em><em>-</em><em> </em><em>2</em>
t = 54 / 2
t = 27
Hence, the time left before the appointed time is 27 minutes.
Learn more : brainly.com/question/25669152
The square root of 72 is rational because the answer can be a real number.
Answer:
-0.924
Step-by-step explanation:
The magnitude of the correlation coefficient is the square root of the variation.
|r| = √0.854
|r| = 0.924
The sign of the correlation coefficient is the same as the slope of the line of best fit. In this case, it's negative.
r = -0.924
First you have to have the absolute value isolated so the 2 has to be divided. Then set up the two cases and solve.
Ok so substitute the values. a=3 b=2 and c=-3
-3^(2)-3(2)^(3)+(-3)^(2)+2(2)^(3)-(-3)^(2)=-9-24+9+16-9=-33+25-9=-42+25=-17
