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lana66690 [7]
3 years ago
6

The reason for the trend in the previous question is because Bromine is _________electron density from the carbon the proton is

on, resulting in the proton being ___________, thus the proton nuclei is_________ effected by the applied magnetic field leading to a greater difference in energy of the nuclei's spin states.
Chemistry
1 answer:
Setler79 [48]3 years ago
5 0

Answer:

Explanation:

From this question, we are to fill in the blanks with the appropriate correct answers.

<u />\text{The reason for the trend in the previous question is because Bromine is } \mathbf{withdrawing}\text{electron density from the carbon the proton is on, resulting in the proton being }\mathbf{deshielded, }\text{thus the proton nuclei is} \ \ \mathbf{more}  \ \ \text{effected by the applied magnetic field leading to a }

\text{greater difference in energy of the nuclei's spin states.}

NOTE: that the electron-withdrawing groups decrease the electron density around the proton nucleus and therefore the nucleus feels the external magnetic field more. Hence, it requires a larger frequency to attain resonance(downfield).

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