.ANSWER:Copper is a ductile metal
EXPLAIN :This means that it can easily be shaped into pipes and drawn into wires. Copper pipes are lightweight because they can have thin walls. They don't corrode and they can be bent to fit around corners.
Answer:
Explanation:
1) a, b) A <em>solution</em><em> is a homogeneous mixture of two or more substances</em>. The <em>solute</em><em> is the substance present in a smaller amount</em>, and the <em>solvent</em><em> is the substance present in a larger amount. </em>
c) <em>A </em><em>saturated solution</em><em> contains the maximum amount of a solute that will dissolve in a given solvent at a specific temperature. </em>
2) See picture in attachment.
Answer:
Equilibrium constant Kc = Qc = quotient of reactant(s) and product(s)
Kc = [C]x[D]y..../[A]m[B]n..... = 0.328dm3/mol, where [C]x[D]y is the product and [A]m[B]n is the reactant(Both in gaseous states)
Explanation:
When a mixture of reactants and products of a reaction reaches equilibrium at a given temperature, its reaction quotient always has the same value. This value is called the equilibrium constant (K) of the reaction at that temperature. As for the reaction quotient, when evaluated in terms of concentrations, it is noted as Kc.
That a reaction quotient always assumes the same value at equilibrium can be expressed as:
Qc (at equilibrium) = Kc =[C]x[D]y…/[A]m[B]n…
This equation is a mathematical statement of the law of mass action: When a reaction has attained equilibrium at a given temperature, the reaction quotient for the reaction always has the same value.
Answer:
2.23M
Explanation:
Molarity of a solution is calculated thus
Molarity = number of moles (n) ÷ volume (V)
According to this question, 4.11g of Zn metal was used in order to reach a volume of EDTA solution of 28.26 mL.
28.26mL = 28.26/1000
= 0.02826L
Using mole = mass/molar mass to calculate no. of moles of Zn
Mole = 4.11/65.4
mole = 0.0628mol
Molarity = 0.0628 ÷ 0.02826
Molarity = 2.23M
The concentration of the EDTA solution used is 2.23M
HI acts as an arrhenius acid in solution. It will dissociate into H⁺ and I⁻ therefore being a proton donor. (HI is actually one of the 7 strong acids)
I hope this helps.
