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bulgar [2K]
2 years ago
12

A projectile is launched with a velocity of 13.2m/s at an angle of 37 degrees above the horizontal. What is the horizontal compo

nent of the projectiles velocity 1s after the object is fired. PLS HURRY THIS IS TIMEd
Physics
1 answer:
MrRissso [65]2 years ago
8 0

Answer:

horizontal component = 10.54m/s

Explanation:

horizontal component = 13.2cos37°

horizontal component = 10.54m/s

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3 years ago
To pull a 57 kg crate across a horizontal frictionless floor, a worker applies a force of 230 N, directed 34° above the horizont
lisabon 2012 [21]

Answer:

a.  W_w=235\ J\\b. W_g=-343.54\ J\\c. F_N=463.100\ N\\d.  W_t=235\ J

Explanation:

Given: that,

Angle of inclination of the surface, \theta=34^{\circ}

mass of the crate, m=57\ kg

Force applied along the surface, F=230\ N

distance the crate moves after the application of force, s=1.1\ m

a) work done = F× s

 work done = 230 × 1.1

 work done = 253 J

b) Work done by the gravitational force:

W_g=m.g\times h

where:

g = acceleration due to gravity

h = the vertically downward displacement

Now, we find the height:

h=s\times sin\ \thetah=1.1\times sin\ 34^{\circ}h=0.615\ m

So, the work done by the gravity:

W_g=57\times 9.8\times (-0.615) \\= - 343.54 J

∵direction of force and displacement are opposite.

= - 343.54J

c)

The normal reaction force on the crate by the inclined surface:

F_N=m.g.cos\ \thetaF_N=57\times 9.8\times cos\ 34F_N=463.100\ N

d)

Total work done on crate is with respect to the worker:

W_t=235\ J

5 0
3 years ago
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