A projectile is launched with a velocity of 13.2m/s at an angle of 37 degrees above the horizontal. What is the horizontal compo
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The Gravitationa potential energy of the mass (PEG) is given by:
where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)
In this problem,
and 
, therefore the gravitational potential energy of the mass is:
where
m is the mass
g is the gravitational acceleration
h is the heigth of the mass above the reference level (the ground)
In this problem,
Answer:
1/9
Explanation:
<em>Newton’s Law of Universal Gravitation </em>
Objects with mass feel an attractive force that is proportional to their masses and inversely proportional to the square of the distance.
F = GMm/r²
where
F - the gravitatioal force in Newtons,
M and m -two masses in kilograms
r - the separation in meters.
G - the gravitational constant (6.674*10 ⁻¹¹ N (m/kg) ² )
Because of the magnitude of G , gravitational force is very small unless large masses are involved.
So according to above equation , when the masses are not changing , force is inversely propotional to the square of distance
F1 ∝ 1/r² ---------------(1)
F2 ∝ 1(3r)²
F2 ∝ 1/9r²--------------(2)
(2)/(1)
From their you get as the distance tripled, Force reduce by a factor of 9(3³)
for example , assume the distance get doubled ,Force reduce by a factor of 4 (2²)