(a) The velocity ratio of the screw is 1570.8.
(b) The mechanical advantage of the screw is 785.39.
<h3>
Velocity ratio of the screw</h3>
The velocity ratio of the screw is calculated as follows;
V.R = 2πr/P
where;
- P is the pitch = 1/10 cm = 0.1 cm = 0.001 m
- r is radius = 25 cm = 0.25 m
V.R = (2π x 0.25)/(0.001)
V.R = 1570.8
<h3>Mechanical advantage of the screw</h3>
E = MA/VR x 100%
0.5 = MA/1570.8
MA = 785.39
Learn more about mechanical advantage here: brainly.com/question/18345299
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It’s e 2.0 x 10^-4 because it is a fraction
Answer:
The current through the inductor at the end of 2.60s is 9.7 mA.
Explanation:
Given;
emf of the inductor, V = 41.0 mV
inductance of the inductor, L = 13 H
initial current in the inductor, I₀ = 1.5 mA
change in time, Δt = 2.6 s
The emf of the inductor is given by;
![V = L\frac{di}{dt} \\\\V = \frac{L(I_1-I_o)}{dt} \\\\L(I_1-I_o) = V*dt\\\\I_1-I_o = \frac{V*dt}{L}\\\\I_1 = \frac{V*dt}{L} + I_o\\\\I_1 = \frac{41*10^{-3}*2.6}{13} +1.5*10^{-3}\\\\I_1 = 8.2*10^{-3} + 1.5*10^{-3}\\\\I_1 = 9.7 *10^{-3} \ A\\\\ I_1 = 9.7 \ mA](https://tex.z-dn.net/?f=V%20%3D%20L%5Cfrac%7Bdi%7D%7Bdt%7D%20%5C%5C%5C%5CV%20%3D%20%5Cfrac%7BL%28I_1-I_o%29%7D%7Bdt%7D%20%5C%5C%5C%5CL%28I_1-I_o%29%20%3D%20V%2Adt%5C%5C%5C%5CI_1-I_o%20%3D%20%5Cfrac%7BV%2Adt%7D%7BL%7D%5C%5C%5C%5CI_1%20%3D%20%20%5Cfrac%7BV%2Adt%7D%7BL%7D%20%2B%20I_o%5C%5C%5C%5CI_1%20%3D%20%5Cfrac%7B41%2A10%5E%7B-3%7D%2A2.6%7D%7B13%7D%20%2B1.5%2A10%5E%7B-3%7D%5C%5C%5C%5CI_1%20%3D%208.2%2A10%5E%7B-3%7D%20%2B%201.5%2A10%5E%7B-3%7D%5C%5C%5C%5CI_1%20%3D%209.7%20%2A10%5E%7B-3%7D%20%5C%20A%5C%5C%5C%5C%20I_1%20%3D%209.7%20%5C%20mA)
Therefore, the current through the inductor at the end of 2.60 s is 9.7 mA.
During the collision between two balls on the pool table there is no external force along the line of collision between them
Since there is no external force on it so here we can say
![F = 0 = \frac{\Delta P}{\Delta t}](https://tex.z-dn.net/?f=F%20%3D%200%20%3D%20%5Cfrac%7B%5CDelta%20P%7D%7B%5CDelta%20t%7D)
here we have
![\Delta P = 0](https://tex.z-dn.net/?f=%5CDelta%20P%20%3D%200)
so we can say
![P_i = P_f](https://tex.z-dn.net/?f=P_i%20%3D%20P_f)
since there is no external force so we can say during the collision the momentum of two balls will remain conserved
The answer is D have a nice day!