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bulgar [2K]
3 years ago
12

A projectile is launched with a velocity of 13.2m/s at an angle of 37 degrees above the horizontal. What is the horizontal compo

nent of the projectiles velocity 1s after the object is fired. PLS HURRY THIS IS TIMEd
Physics
1 answer:
MrRissso [65]3 years ago
8 0

Answer:

horizontal component = 10.54m/s

Explanation:

horizontal component = 13.2cos37°

horizontal component = 10.54m/s

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The distance between the centers of the wheels of a motorcycle is 156 cm. The center of mass of the motorcycle, including the ri
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Answer:

a = 9.86 m/s²

Explanation:

given,

distance between the centers of wheel = 156 cm

center of mass of motorcycle including rider = 77.5 cm

horizontal acceleration of motor cycle = ?

now,

The moment created by the wheels must equal the moment created by gravity.

take moment about wheel as it touches the ground, here we will take horizontal distance between them.

then, take the moment around the center of mass. Since the force on the ground from the wheels is horizontal, we need the vertical distance.

now equating both the moment

m g d = F h

d is the horizontal distance

h is the vertical distance

m g d = m a h

term of mass get eliminated

g d = a h

so,

a = \dfrac{g\ d}{h}

a = \dfrac{9.8\times 0.78}{0.775}

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4 0
3 years ago
The wavelength of an electron whose velocity is 1.7 Ã 104 m/s and whose mass is 9.1 Ã 10-28 g is ________ m. the wavelength of a
madreJ [45]
<span>Mass of the electron = 9.1 x 10 ^ -28g = 9.1 x 10 ^ -31kg Velocity of the electron = 1.7 x 10 ^ 4 We have Planck Constant h = 6.626 x 10 ^ -34 Wavelength of the electron w = h/mv w = 6.626 x 10 ^ -34 / ((9.1 x 10 ^ -31)(1.7 x 10 ^ 4)) = 6.626 x 10 ^ -34 / 15.47 x 10 ^ -27 = 0.428312 x 10 ^ -7 = 4.28 x 10 ^ -8 m</span>
4 0
3 years ago
Technically, how would you know if any work was done on an object?
kherson [118]

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through reading the question carefully and using yourself as an exampke

8 0
2 years ago
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liq [111]

Answer:

T = 3183 N

Explanation:

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\Delta L = 12.56 mm

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Y = \frac{T/A}{\Delta L/L}

so we have

T = \frac{AY \Delta L}{L}

T = \frac{\pi (0.55 \times 10^{-3})^2(2.0 \times 10^{11})(12.56 \times 10^{-3})}{0.75}

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3 0
3 years ago
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atroni [7]

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