Answer : The maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.
Solution : Given,
Mass of
= 28 g
Mass of
= 190 g
Molar mass of
= 32 g/mole
Molar mass of
= 30 g/mole
Molar mass of
= 44 g/mole
First we have to calculate the moles of
and
.
![\text{ Moles of }C_2H_6=\frac{\text{ Mass of }C_2H_6}{\text{ Molar mass of }C_2H_6}=\frac{28g}{30g/mole}=0.933moles](https://tex.z-dn.net/?f=%5Ctext%7B%20Moles%20of%20%7DC_2H_6%3D%5Cfrac%7B%5Ctext%7B%20Mass%20of%20%7DC_2H_6%7D%7B%5Ctext%7B%20Molar%20mass%20of%20%7DC_2H_6%7D%3D%5Cfrac%7B28g%7D%7B30g%2Fmole%7D%3D0.933moles)
![\text{ Moles of }O_2=\frac{\text{ Mass of }O_2}{\text{ Molar mass of }O_2}=\frac{190g}{32g/mole}=5.94moles](https://tex.z-dn.net/?f=%5Ctext%7B%20Moles%20of%20%7DO_2%3D%5Cfrac%7B%5Ctext%7B%20Mass%20of%20%7DO_2%7D%7B%5Ctext%7B%20Molar%20mass%20of%20%7DO_2%7D%3D%5Cfrac%7B190g%7D%7B32g%2Fmole%7D%3D5.94moles)
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
![2C_2H_6+7O_2\rightarrow 4CO_2+6H_2O](https://tex.z-dn.net/?f=2C_2H_6%2B7O_2%5Crightarrow%204CO_2%2B6H_2O)
From the balanced reaction we conclude that
As, 2 mole of
react with 7 mole of ![O_2](https://tex.z-dn.net/?f=O_2)
So, 0.933 moles of
react with
moles of ![O_2](https://tex.z-dn.net/?f=O_2)
From this we conclude that,
is an excess reagent because the given moles are greater than the required moles and
is a limiting reagent and it limits the formation of product.
Now we have to calculate the moles of ![CO_2](https://tex.z-dn.net/?f=CO_2)
From the reaction, we conclude that
As, 2 mole of
react to give 4 mole of ![CO_2](https://tex.z-dn.net/?f=CO_2)
So, 0.933 moles of
react to give
moles of ![CO_2](https://tex.z-dn.net/?f=CO_2)
Now we have to calculate the mass of ![CO_2](https://tex.z-dn.net/?f=CO_2)
![\text{ Mass of }CO_2=\text{ Moles of }CO_2\times \text{ Molar mass of }CO_2](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20%7DCO_2%3D%5Ctext%7B%20Moles%20of%20%7DCO_2%5Ctimes%20%5Ctext%7B%20Molar%20mass%20of%20%7DCO_2)
![\text{ Mass of }CO_2=(1.87moles)\times (44g/mole)=82.3g](https://tex.z-dn.net/?f=%5Ctext%7B%20Mass%20of%20%7DCO_2%3D%281.87moles%29%5Ctimes%20%2844g%2Fmole%29%3D82.3g)
Therefore, the maximum mass of carbon dioxide produced by the chemical reaction can be, 82.3 grams.