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4 years ago

7 places that carbon exists

Physics

1 answer:

BigorU [14]4 years ago

7 0

Trees
Animals
Grass
Minerals
Coal
Fossil fuels
Natural gas

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Look at the illustration pictured above. The focal point(s) in this design is/are found at the design's

pickupchik [31]

Where is the picture??

5 0

4 years ago

Which does not provide a significant voltage difference in a circuit?

Gnom [1K]

Answer:

<em>b - wires</em>

Explanation:

cells , dry cells , electrical outlets are all responsible for the varying electron pressure/ potential difference hence wires is our answer because wires are just conductors which can only influence resistance.

5 0

3 years ago

From the edge of a cliff, a 0.46 kg projectile is launched with an initial kinetic energy of 1430 J. The projectile's maximum up

wel

Answer:

Explanation:

Given

mass of Projectile(m)=0.46 kg

Initial Kinetic Energy=1430 J

Maximum upward displacement from Launch point=150 m

$K.E.=\frac{mv^2}{2}$

$1430\times 2=0.46\times v^2$

v=78.85 m/s

and $H_{max}=\frac{v^2\sin ^2\theta }{2g}$

$150=\frac{(78.85)^2\sin ^2\theta }{2\times 9.8}$

$\sin \theta =0.687$

$\theta =43.39^{\circ}$

initial horizontal velocity $(v_x)=v\cos \theta$

$v_x=78.84\times \cos (43.39)=57.29 m/s$

Initial vertical velocity $(v_y)=v\sin \theta$

$v_y=78.85\times \sin (43.39)$

$v_y=54.16 m/s$

(c)vertical velocity at any instant=65 m/s

Since initial vertical velocity is 54.16 m/s

so 65 m/s will be acquired when projectile started falling below cliff

$v^2-u^2=2 a s$

$65^2-54.16^2=2\times 9.8\times s$

$s=65.90 m$

7 0

3 years ago

The four best metallic conductors are: A. gold B. cadmium C. alloys D. copper E. silver F. sodium G. aluminum H. iron I have to

RoseWind [281]

Answer:

Explanation:

I can give you four for certain.

Copper

Gold

Silver

Aluminum

7 0

3 years ago

A 2.0-kilogram mass is located 3.0 meters above

leva [86]

The correct answer is: Option (3) 9.8 N/kg

Explanation:

According to Newton's Law of Gravitation:

$F_g = \frac{GmM}{R^2}$ --- (1)

Where G = Gravitational constant = 6.67408 × 10⁻¹¹ m³ kg⁻¹ s⁻²

m = Mass of the body = 2 kg

M = Mass of the Earth = 5.972 × 10²⁴ kg

R = Distance of the object from the center of the Earth = Radius of the Earth + Object's distance from the surface of the Earth = (6371 * 10³) + 3.0 = 6371003 m

Plug in the values in (1):

(1)=> $F_g = \frac{6.67408 * 10^{-11} * 2 * 5.972*10^{24}}{(6371003)^2} = 19.63$

Now that we have force strength at the location, we can use:

Force = mass * gravitational-field-strength

Plug in the values:

19.63 = 2.0 * gravitational-field-strength

gravitational-field-strength = 19.63/2 = 9.82 N/kg

Hence the correct answer is Option (3) 9.8 N/kg

4 0

4 years ago

Read 2 more answers