Ask question

Ask question

All categories

Keith_Richards [23]

3 years ago

14

Two identical wheels, wheel 1 and wheel 2, initially at rest begin to rotate with constant angular accelerations α. After rotati

ng through the same angular displacement, Δθ0, the angular velocity of wheel 1 is ω1 and the angular velocity of wheel 2 is ω2=3ω1. How does the angular acceleration of wheel 2, α2, compare to the angular acceleration of wheel 1, α1?a. a2 = a1b. a2 = a1/3c. a2 = 3a1d. a2 = 9a1

2 answers:

Thepotemich [5.8K]3 years ago

6 0

Answer:

a2 = 3a1

Explanation:

Detailed explanation and calculation is shown in the image below

Georgia [21]3 years ago

5 0

Answer:

d. a2 = 9a1

Explanation:

We can apply the following equation of motion to calculate the angular acceleration:

$\omega^2 - \omega_0^2 = 2\alpha\theta$

Since both wheel starts from rest, their $\omega_0 = 0 rad/s$

$\omega^2 = 2\alpha\theta$

We can take the equation for the 1st wheel, divided by the equation by the 2nd wheel:

$\frac{\omega_1^2}{\omega_2^2} = \frac{2\alpha_1\theta_1}{2\alpha_2\theta_2}$

As they were rotating through the same angular displacement $\theta_1 = \theta_2$ , these 2 cancel out

$\left(\frac{\omega_1}{\omega_2}\right)^2 = \frac{\alpha_1}{\alpha_2}$

$\left(\frac{1}{3}\right)^2 = \frac{\alpha_1}{\alpha_2}$

$\frac{1}{9} = \frac{\alpha_1}{\alpha_2}$

$\alpha_2 = 9\alpha_1$

So d is the correct answer

You might be interested in

Earths gravitational pull just got 3 times stronger what happens to your weight?

djverab [1.8K]

You get 3 times heavier

6 0

3 years ago

Read 2 more answers

Sports managers have the potential to earn more than a million dollars per year.<br> True<br> false

andriy [413]

Answer:

true

Explanation:

hope this helped!

4 0

2 years ago

A cardio kickboxing class challenges 3 things. List them.

bagirrra123 [75]

Answer:

In a cardio kickboxing class, you will learn proper form for the famous jab, hooks,crosses, uppercuts, back kicks, front kicks.

Explanation:

6 0

2 years ago

Two thin concentric spherical shells of radii r1 and r2 (r1 < r2) contain uniform surface charge densities V1 and V2, respect

Lyrx [107]

Answer:

Answer is explained in the explanation section below.

Explanation:

Solution:

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

So,

a) 0 < r < r1 :

We know that the Electric field inside the thin hollow shell is zero, if there is no charge inside it.

Hence, E = 0 for r < r1

b) r1 < r < r2:

Electric field =?

Let, us consider the Gaussian Surface,

E x 4 $\pi$ $r^{2}$ = $\frac{Q1}{E_{0} }$

So,

Rearranging the above equation to get Electric field, we will get:

E = $\frac{Q1}{E_{0} . 4 \pi. r^{2} }$

Multiply and divide by $r1^{2}$

E = $\frac{Q1}{E_{0} . 4 \pi. r^{2} }$ x $\frac{r1^{2} }{r1^{2} }$

Rearranging the above equation, we will get Electric Field for r1 < r < r2:

E= (σ1 x $r1^{2}$ ) /( $E_{0}$ x $r^{2}$ )

c) r > r2 :

Electric Field = ?

E x 4 $\pi$ $r^{2}$ = $\frac{Q1 + Q2}{E_{0} }$

Rearranging the above equation for E:

E = $\frac{Q1+Q2}{E_{0} . 4 \pi. r^{2} }$

E = $\frac{Q1}{E_{0} . 4 \pi. r^{2} }$ + $\frac{Q2}{E_{0} . 4 \pi. r^{2} }$

As we know from above, that:

$\frac{Q1}{E_{0} . 4 \pi. r^{2} }$ = (σ1 x $r1^{2}$ ) /( $E_{0}$ x $r^{2}$ )

Then, Similarly,

$\frac{Q2}{E_{0} . 4 \pi. r^{2} }$ = (σ2 x $r2^{2}$ ) /( $E_{0}$ x $r^{2}$ )

So,

E = $\frac{Q1}{E_{0} . 4 \pi. r^{2} }$ + $\frac{Q2}{E_{0} . 4 \pi. r^{2} }$

Replacing the above equations to get E:

E = (σ1 x $r1^{2}$ ) /( $E_{0}$ x $r^{2}$ ) + (σ2 x $r2^{2}$ ) /( $E_{0}$ x $r^{2}$ )

Now, for

d) Under what conditions, E = 0, for r > r2?

For r > r2, E =0 if

σ1 x $r1^{2}$ = - σ2 x $r2^{2}$

4 0

3 years ago

The work output of a machine divided by the work input is the ____ of the machine.

s344n2d4d5 [400]

<span>The work output of a machine divided by the work input is the "Efficiency" of the machine.

Hope this helps!</span>

7 0

3 years ago