A metaphor is<span> a comparison between two non related objects where the first object is said to be equal to the second.</span>
The answer is d.
Answer:
the maximum height reached by the object from where it was launched is 0.4591 m
Explanation:
initial speed of the object, u= 3 m/s
The velocity at the maximum height will always be 0.
Therefore, final velocity, v= 0 m/s
Using the Newton's equation of motion,
v^2 - u^2 = 2*g*h(max)
0 - u^2= 2*g*h(max)
h(max) = -u^2 /2* g
where g is the gravitational acceleration.
g= - 9.8 m/s^2
substituting the values in equation,
h(max)= - (3*3) / 2*(-9.8)
h(max) = 0.4591 m
the maximum height reached by the object from where it was launched is 0.4591 m
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Answer:

Explanation:
mass of the ball = 0.25 kg
its speed v = 4.5 m/s
r = 0.75 m
let the speed be in the horizontal direction and the distance r be in the vertical direction we have :


Let the momentum about the center of intersection be P;
SO;



Let the angular momentum be Q;



Explanation:
the third answer is correct
71.5m/s
Answer:
zone of saturation
Explanation:
The water table is the upper limit of the zone of saturation. At the zone of saturation, the aquifers are filled with water completely. The void spaces within the rock particles are taken up by fluids.
The upper limit of this zone is the water table.
Above the water table is the zone of aeration where the pore spaces are filled within air.
During the time of recharge especially raining seasons, part of the zone of aeration are filled with water.