Answer:
The velocity of the man is 0.144 m/s
Explanation:
This is a case of conservation of momentum.
The momentum of the moving ball before it was caught must equal the momentum of the man and the ball after he catches the ball.
Mass of ball = 0.65 kg
Mass of the man = 54 kg
Velocity of the ball = 12.1 m/s
Before collision, momentum of the ball = mass x velocity
= 0.65 x 12.1 = 7.865 kg-m/s
After collision the momentum of the man and ball system is
(0.65 + 54)Vf = 54.65Vf
Where Vf is their final common velocity.
Equating the initial and final momentum,
7.865 = 54.65Vf
Vf = 7.865/54.65 = 0.144 m/s
Answer:
8 and 093 over 0.6 then 303
Explanation:
cross over the numbers and get the answer
Answer:
(2.5,0)
Explanation:
The particle can be described by the following equations:
For R = 2.5, ω = 2 and t = 0:
The center of the circle would be at point (2.5,0)
It is a question that leads us to know the proportion of one element to another. We have initially that the mass of the earth is of
m_E = 5.98*10^{24}kg
While the mass of the Moon is of
m_M = 7.35*10^{22}kg
The ratio between the two is given by the function
This means that the mass of the earth is 81.36 times larger than that of the Moon.
