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earnstyle [38]
3 years ago
9

A box is initially at rest on a horizontal, frictionless table. If a force of 10

Physics
1 answer:
lukranit [14]3 years ago
8 0

Answer: 18

Explanation:

i think

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There are 3 states of matter. Solid, Liquid, Gas. An example of each would be ice, water, steam,
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2 years ago
A 50.0 g toy car is released from rest on a frictionless track with a vertical loop of radius R (loop-the-loop). The initial hei
Mariana [72]

Answer:

the speed of the car at the top of the vertical loop  v_{top} = 2.0 \sqrt{gR \ \ }

the magnitude of the normal force acting on the car at the top of the vertical loop   F_{N} = 1.47 \ \ N

Explanation:

Using the law of conservation of energy ;

mgh = mg (2R) + \frac{1}{2}mv^2_{top}\\\\mg ( 4.00 \ R) = mg (2R) + \frac{1}{2}mv^2_{top}\\\\g(4.00 \ R) = g (2R) + \frac{1}{2}v^2 _{top}\\\\v_{top} = \sqrt{2g(4.00R - 2R)}\\\\v_{top} = \sqrt{2g(4.00-2)R

v_{top} = 2.0 \sqrt{gR \ \ }

The  magnitude of the normal force acting on the car at the top of the vertical loop can be calculated as:

F_{N} = \frac{mv^2_{top}}{R} \ - mg\\\\F_{N} = \frac{m(2.0 \sqrt{gR})^2}{R} \ - mg\\\\F_{N} = [(2.0^2-1]mg\\\\F_{N} = [(2.0)^2 -1) (50*10^{-3} \ kg)(9.8 \ m/s^2]\\\\

F_{N} = 1.47 \ \ N

4 0
3 years ago
What is the formula for momentum?
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The momentum of any object is (the object's mass) times (its speed).


8 0
3 years ago
A car initially at rest undergoes uniform acceleration for 6.32 seconds and covers a distance of 120 meters. What is the approxi
Alja [10]
The approximate acceleration of the car would be <span>3.00

</span>How? We have to use the formula to find the velocity.

v = d/t = 120/6.32

v = 19

Then plug the factor into the acceleration formula to find the acceleration:

a = v/t = 19/6.32

a = 3.00

So, the approximate acceleration of the car would be 3.00
4 0
4 years ago
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