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2 years ago

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Calculate the frequency of a sound wave produced when a tennis racquet string is plucked. The tension of the string is 274 N, th

e mass of the string is 28 kg and the length of the string is 0.74 m.

1 answer:

diamong [38]2 years ago

4 0

Answer:

Explanation:

The velocity of sound from the plucked string in the tennis racquet is:

$v=\sqrt{\frac{FL}{m}}=\sqrt{\frac{274(0.74)}{28}}\approx 2.69 ms^{-1}$

Then the frequency will be:

$f=\frac{v}{2L}=\frac{2.69}{2(0.74)}\approx 1.81 Hz$

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dry air is way heaver

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2 years ago

There is a naturally occurring vertical electric field near the Earth’s surface that points toward the ground. In fair weather c

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Answer:

$\frac{F}{W} = 9.37 \times 10^{-4}$

Explanation:

Radius of the pollen is given as

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$V = \frac{4}{3}\pi (12\mu m)^3$

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mass of the pollen is given as

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$m = 7.24 \times 10^{-12}$

so weight of the pollen is given as

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$W = (7.24 \times 10^{-12})(9.81)$

$W = 7.1 \times 10^{-11}$

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$\frac{F}{W} = 9.37 \times 10^{-4}$

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2 years ago

A 7.36 g sample of copper is contaminated with a additional 0.51 g sample of zinc. Suppose an atomic mass measurement was perfor

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The molar mass of the sample is equal to the summation of the molar mass of the elementas multiplied by the abundance of the elements by mole. In this case, copper has an abundance of 93.69 percent while zinc has 6.31 percent. In this case, the average molecular weight is 63.67 g/mol

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3 years ago

A car with a velocity of 22 m/s is accelerated at a rate of 1.6m/s2 for 6.8s. determine the final velocity

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A car with a velocity of 22 m/s is accelerated at a rate of 1.6 $m/s^2$ for 6.8s has the final velocity t be 32.88 m/s.

The acceleration means the amount of velocity changing per unit time.

The given data:

initial velocity, u = 22 m/s

time, t = 6.8 s

acceleration, a = 1.6 $m/s^2$

We will be using the equation of motion:

v = u + at

$\therefore v=22+1.(6.8)$

$\Rightarrow v=22+10.88$

$\Rightarrow v=32.88 \ m/s$

The final velocity become 32.88 m/s.

To learn more about Attention here:

https://brainly.in/question/10557838

#SPJ4

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1 year ago

If a person is 6.25 m away from a 60.0 w speaker, what is the sound level they are hearing?

vodka [1.7K]

Answer:

110.87 dB

Explanation:

(I got it right on Acellus)

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B=10log(I/Io)

B=10log(0.12223/1*10^-12) = 110.87 dB

111 in sigfigs

4 0

2 years ago

Read 2 more answers