2 years ago

QUESTION 8: When would acceleration increase most? *

Chemistry

1 answer:

sergey [27]2 years ago

5 0

Answer:

Rolling down a steep hill

Explanation:

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A force of 20 N acts upon 5 kg block caculate the accerleration of the object

Vedmedyk [2.9K]

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$\boxed{\text{4 m $\cdot$ s$^{-2}$}}$

Explanation:

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$a = \dfrac{F}{m} = \dfrac{\text{20 N}}{\text{5 kg}} \times \dfrac{\text{1 kg$\cdot$ m $\cdot$ s$^{-2}$}}{\text{1 N}} = \text{4 m $\cdot$ s$^{-2}$}\\\\\text{The acceleration of the object is } \boxed{\textbf{4 m $\cdot$ s$^{\mathbf{-2}}$}}$