Answer:
3 water molecules
Explanation:
The molar ratio between CuSO₄ and H₂O needs to be calculated.
The mass of water that was removed by heating is calculated, then converted to moles. The molecular weight of water is 18.02g/mol.
(8.97 g - 6.57 g) = 2.22 g H₂O
(2.22 g)/(18.02g/mol) = 0.1232 mol H₂O
The moles of anhydrous copper sulfate are calculated. The molecular weight is 159.609 g/mol
(6.57 g)/(159.609 g/mol) = 0.04116 mol CuSO₄
Now the molar ratio between CuSO₄ and H₂O can be calculated:
0.1232 mol H₂O ÷ 0.04116 mol CuSO₄ = 3 H₂O / CuSO₄
The focal length of the mirror is 15 cm
From the question given above, the following data were obtained:
Object distance (u) = 30 cm
Image distance (v) = 30 cm
<h3>Focal length (f) =? </h3>
The focal length of the mirror can be obtained as follow:
<h3>Invert </h3><h3>f = 15 cm</h3>
Therefore, the focal length of the mirror is 15 cm
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The correct answer is - False.
The soils are part of most of the major cycles that take place on the Earth, mainly because they are in touch with the other spheres. The carbon dioxide, as well as the nitrogen and the sulfur cycles too, end up in the soil in more cases than not during their cycles. While some are formed in it and than released, like the sulfur, the carbon mostly gets in it though the roots of the plants, as well as the decomposing organisms, and the nitrogen ends up in the soil with the water.
The soil is one of the most important pieces in the cycles of most of the gases on Earth, and without it, some will not even be possible.
Single-celled organisms<span> which use asexual reproduction can </span>do<span> so very rapidly simply by </span>dividing<span> into two equal halves. This is called binary fission. In yeasts the </span>cell<span> does not </span>divide<span> equally in two halves; instead, there is a large mother </span>cell<span> and a smaller daughter </span>cell<span>. This is called budding.</span>
The balanced chemical
reaction will be:
2H2O = 2H2 + O2
<span>We are given the amount of water used in the decomposition reaction. This will be our
starting point.</span>
<span>17.0 g H2O</span> (1 mol H2O/ 18.02 g H2O) (1 mol O2/2
mol <span>H2O</span>) ( 32.00 g O2/1mol O2) = 15.09 g O2
Percent yield = actual yield / theoretical yield x 100
<span>Percent yield =10.2 g / 15.09 g
x 100</span>
Percent yield = 67.58%