Answer:
Explanation:
In this case the answer would be
Water is a polar molecule with positive and negative side
Now since these negative and positives are present in the water molecule . In easy terms when a substance reacts with water .the negative part of water ( oxygen ) reacts with the positive part of the substance and the positive part of the water ( hydrogen) reacts with negative part of the substance .if you look at the reason . Water is held up by one of the strongest attraction forces available .since most substances have weaker attraction forces between them ,therefore water can easily overcome them with its forces. Thus giving it the ability to dissolve a variety of substances
Answer:
B C A
Explanation:
because as you pour the blue stuff in it will straight up go to the bottom (and has less blue coloring) Then it will go to the top (lil more blue coloring) then eventually the whole jar will be blue
hope this helps you out bro
Arkeisha is correct because the fluid in an alkaline battery has a ph between 7.1 and 14.0
Ionic bond is formed between positive and negative ions.
Positive ion is known as cation (electropositive metal)
Negative ion is known as anion ( electronegative non-metal)
The bond formed between a metal (positive ion) and non-metal (negative ions) is known as Ionic bond.
Ionic form is formed when one or more electrons from the valence shell of an atom (electropositive metal ) are completely transferred to the valence shell of another atom (electronegative non-metal). Ionic bonding is the complete transfer of valence electron(s) between oppositely charged atoms.
For example: Bond between NaCl(sodium chloride) is an ionic bond in which Na (sodium ) is positive ion(metal) which have +1 charge and Cl (chlorine) is negative ion(non-metal) which have -1 charge and the bond formed between Na+ and Cl- is ionic bond.
Answer:
0.34 M
Explanation:
I assume that the compound is PbCl2.
One mole of PbCl2 contains one mol of Pb+2 and 2 moles of Cl-
Molarity (M)= moles (n) /Volume (V)
Moles Pb2+ = M x V = 0.17 V
Moles Cl- = moles Pb2+ x (2 moles Cl-/1 mole Pb2+) = 0.17 V x 2 = 0.34 V
M Cl- = moles Cl-/V = 0.34V/V = 0.34 M
