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andrey2020 [161]
3 years ago
12

James measured the humidity of the air on his backyard each morning for four days His data is recorded below On which day did it

most likely rain
Chemistry
1 answer:
Over [174]3 years ago
3 0

Answer:

hdbdjsjsj

Explanation:

hdhshshe

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Which series reveals the source of energy for oil? please help ASAP!!! WILL MARK BRAINLEST
Murrr4er [49]

Answer:

B

Explanation:

Oil > Animals > Plants > Chemicals

5 0
2 years ago
Read 2 more answers
Wuy Piolcululugu<br> Give the names of two organs in the chest.<br> 1. ...............<br> 2 m
Arada [10]

Answer:

The organs present inside the chest are :

1. The lungs

2. The heart

Explanation:

The chest cavity is also called as the thoracic cavity. It is the second largest hollow space of the body.In the bottom , it is enclosed by the diaphragm.

This cavity actually contain three space each round with mesothelium , pleural cavity and precardial cavity.

This contain the lungs , the tracheobronchial tree , the heart , the blood vessels which transport the blood between the heart and the lungs.

It also contain the esophagus .

Esophagus is the path through which the food passes from the mouth to the stomach.

8 0
3 years ago
Please help asap! Giving brainliest to correct answer.
Leya [2.2K]

Answer:

C. It may act as an insulator or a conductor.

Explanation:

Group B are the metalloids, so they have properties of both metals and nonmetals.

6 0
2 years ago
Reactants are substances that?
RSB [31]
A substance that undergoes change during a reaction, usually from coming in contact with another substance
4 0
2 years ago
A ball is dropped from a height of 1.20 m and hits the floor. The ball compresses and then reforms to spring upwards from the fl
diamong [38]

Answer:

\large \boxed{\text{98 m$\cdot$s}^{-2}}

Explanation:

The formula for the velocity of the ball is

v = \sqrt{2gh}

1. Velocity at time of impact

v = -\sqrt{2 \times 9.807 \times 1.20} = -\sqrt{23.54} = -\textbf{4.85 m/s}

2. Velocity on rebound

The ball has enough upward velocity to reach a height of 0.86 m.

v = \sqrt{2 \times 9.807 \times 0.86} = \sqrt{16.87} =\textbf{4.11 m/s}

3. Acceleration

a = \dfrac{\Delta v}{\Delta t} = \dfrac{4.11 - (-4.85)}{ 0.091} = \dfrac{8.96 }{0.091} =\textbf{98 m$\cdot$s}^{\mathbf{-2}}\\\\\text{The acceleration while the ball is in contact with the floor is $\large \boxed{\textbf{98 m$\cdot$s}^{\mathbf{-2}}}$}

5 0
3 years ago
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