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AlexFokin [52]
3 years ago
11

The vapor pressure of a liquid __________.

Chemistry
1 answer:
mash [69]3 years ago
6 0

Answer:

B

Explanation:

The tendency of a liquid to convert to vapour increases smoothly with increasing temperature. Vapour pressure shows the tendency of a liquid to convert to vapour. Increase In vapour pressure shows an increased tendency to convert to vapour. The higher the temperature, the higher the vapour pressure.

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Công thức toingr quát anken
Maksim231197 [3]

Answer:

ndcjc  kin ksklp

Explanation:

4 0
3 years ago
Two substances with empirical formula HNO are hyponitrous acid (M = 62.04 g/mol) and nitroxyl (M = 31.02 g/mol).(c) Predict the
Levart [38]

While Nitroxyl, or HNO, has a dihedral form and just one nitrogen, Hyponitrous Acid, N2(OH)2, has both cis and trans structures and contains two nitrogens.

Hyponitrous acid has the chemical formula H2N2O2 or HON=NOH. 62.028 g/mol is the molecular weight of it. Additionally, it can take either a trans or cis form. When dry, the trans-hyponitrous acid crystallizes into white, explosive particles. Recent research has focused on nitroxyl (HNO), the one-electron reduced and protonated congener of nitric oxide (NO), as a potential drug for the treatment of heart failure and as a pre-conditioning agent to prevent ischemia-reperfusion injury, among other potential uses.

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​

5 0
2 years ago
Jones Soda contains 33g added sugar (C6H12O6) in a 355 ml bottle, while Sierra Mist contains 62g added sugar in a 591 ml bottle.
ArbitrLikvidat [17]

C6H12O6 molar mass: 180.15768 g

solute: sugar

molarity = moles of solute / liters of solution

Jones Soda:

33 g / 180.15768 g = 0.18 moles C6H12O6

M = 0.18 g / 0.355 L

M = 0.52

Sierra Mist:

62 g / 180.15768 g = 0.34 moles C6H12O6

M = 0.34 g / 0.591 L

M = 0.58

Sienna Mist has a higher molarity and is more concentrated.

7 0
3 years ago
Give two reasons why scientists create models to study atoms.
mariarad [96]
IT will be easy to know how chemical reactions occur
It will helps to know the fundamental particles of an atom
4 0
3 years ago
Calculate the % composition of the unknown liquid using your most precise result. It is a mixture of ethanol (D[ETOH] = 0.7890 g
Rufina [12.5K]

% composition of ethanol = 34.51%

% composition of water  = 65.49%

<h3>What is density?</h3>

A material's density is defined as its mass per unit volume.

Given data:

The density of ethanol = 0.7890 g/mL

The density of water = 0.9982 g/mL

The density of mixture = 0.926 g/mL

Let the % composition of ethanol = x

Let the % composition of water = 100-x

Now density of the mixture

\frac{Mass}{Volume}

Mass = \frac{percent  \;of  \;ethanol  \;X  \;density  \;of  \;ethanol  \;+  \\ \;percent  \;of  \;water X  \;density  \;of  \;water}{100}

0.926 = \frac{x X  0.7890 g/mL  \;+  (100-x) X  0.9982 g/mL}{100}

x= 34.51 %

Hence,

% composition of ethanol = 34.51%

% composition of water = 65.49%

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8 0
2 years ago
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