I would say D, because you need to start with nothing to measure the different sizes as they start to grow. hope this helps!
        
             
        
        
        
You start numbering from <span>the side with the methyl group and find the longest chain, which is seven = hept. The triple bond is -yne at C3. The methyl group is on C2.
This means that the best name for this molecule is </span><span>2-methyl-3-heptyne.</span>
        
             
        
        
        
Answer:
The concentration of CH₃OH in equilibrium is [CH₃OH] = <em>2,8x10⁻¹ M</em>
Explanation:
For the equilibrium:
CO (g) + 2H₂(g) ⇄ CH₃OH(g) keq= 14,5
Thus:
14,5 = ![\frac{[CH_{3}OH]}{[CO][H_{2}]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5BCO%5D%5BH_%7B2%7D%5D%5E2%7D)
In equilibrium, as [CO] is 0,15M and [H₂] is 0,36M:
14,5 = ![\frac{[CH_{3}OH]}{[0,15][0,36]^2}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BCH_%7B3%7DOH%5D%7D%7B%5B0%2C15%5D%5B0%2C36%5D%5E2%7D)
Solving, the concentration of CH₃OH in equilibrium is:
<em>[CH₃OH] = 0,28M ≡ 2,8x10⁻¹ M</em>
I hope it helps!