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Sergeeva-Olga [200]
3 years ago
8

Four model rockets are launched in a field. The mass of each rocket and the net force acting on it when it launches are given in

the table below. Rocket Which rocket has the lowest acceleration?
Physics
1 answer:
ankoles [38]3 years ago
3 0

Answer:Rocket 2

Explanation:

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An electric dipole consists of a particle with a charge of 6 x 10–6 c at the origin and a particle with a charge of –6 x 10–6 c
mote1985 [20]

An electric dipole consists of a particle with a charge of 6 x 10⁻⁶ c at the origin and a particle with a charge of –6 x 10⁻⁶ c on the x axis at x = 3 x 10⁻³ m. Its dipole moment is 18 x 10⁻⁹ Cm

Dipole moment of a dipole is dependent on the charge of the dipole and the distance between the two charges.

Electric Dipole consists of two charges which are equal and opposite in charge i.e. positive and negative charges.

Given,

Dipole moment, p = ?

Charge, q = 6 x 10⁻⁶C

Distance between charges, d = 3 x 10⁻³ m

Dipole moment (p) is given by:

p = charge x distance between the two charges

p = 6 x 10⁻⁶ x 3 x 10⁻³ Cm

p = 18 x 10⁻⁹ Cm

The dipole moment for the given charge configuration is 18 x 10⁻⁹ Cm

Learn more about Dipole moment here, brainly.com/question/14058533

#SPJ4

8 0
2 years ago
Car A with a mass of 725 kilograms is traveling east at an initial velocity of 15 meters/second. It collides head–on with car B,
ikadub [295]

Answer:

p_t_o_t_a_l=250kg\frac{m}{s}

Explanation:

<u>The total momentum of a system is defined by:</u>

(mv)_t_o_t=m_1v_1+m_2v_2+...

Where,

(mv)_t_o_t is the total momentum or it could be expressed also as p_t_o_t_a_l.

m_1 and m_2 represents the masses of the objects interacting in the system.

v_1 and v_2 are the velocities of the objects of the system.

<em>Remember: </em><em>The momentum is a fundamental physical magnitude of vector type.</em>

We have:

m_1=725 kg

v_1=15\frac{m}{s}\\m_2=625 kg

We are going to take the east side as positive, and the west side as negative. Then the velocity of the car B, has to be <u>negative</u>. It goes in a different direction from car A.

v_2=-17\frac{m}{s}

Then the total momentum of the system is:

p_t_o_t_a_l=m_1v_1+m_2v_2\\p_t_o_t_a_l=(725kg)(15\frac{m}{s})+(625kg)(-17\frac{m}{s})\\p_t_o_t_a_l=10875kg\frac{m}{s}-10625kg\frac{m}{s}\\p_t_o_t_a_l=250kg\frac{m}{s}

8 0
3 years ago
Calculate the force it would take to accelerate a 250 kg motorcycle at a rate of 5 m/s2
Sphinxa [80]

Force = mass x acceleration

Mass is given to be 250kg

Acceleration is given to be 5m/s^2

Force = 250kg x 5m/s^2 = 1,250 kgm/s^2 = 1,250 Newtons

7 0
3 years ago
Read 2 more answers
At which point would most of the pendulum's potential energy have been transformed into kinetic energy?
Bess [88]

Answer:

C

Explanation:

i could be wrong but it seems the most logical

6 0
3 years ago
A car with a mass of 1500 kg is pulled by a rope that is horizontal to the ground. The tension in the rope is 2000 N and a frict
Tanzania [10]

Answer:

Explanation:

Assuming the ground is level as well.

F = ma

a = F/m

a = (2000 - 350) / 1500

a = 1.1 m/s²

7 0
3 years ago
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