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natta225 [31]
3 years ago
12

11. When heat is removed from a solid, what happens?

Chemistry
1 answer:
attashe74 [19]3 years ago
4 0
The answer is A, I hope this helps you!
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PLEASE HELP MEEEEE
igor_vitrenko [27]

Answer:

hey there! it gains an electron and has an octet in its inner shell it loses an electron and has an octet in the next lowest energy level it gains an electron and has an octet in the lowest energy level it gains an electron and has an octet in its outer shell

HAVE A GRET DAY! ;D

Explanation:

tbh idk if im 100% sure if im right but i hope i am :)

8 0
2 years ago
Read 2 more answers
What type of reaction is Mg + 2Ag -> mg2 + 2Ag
bulgar [2K]

Answer:

double replacement ...i think ^^

i hopefully its right

4 0
2 years ago
4Fe+3O2<br><br> I really have no idea how to do this.. HELP
Jlenok [28]
Reorder 4Fe and 3O2.
3O2 + 4Fe
3 0
3 years ago
Part IV. Limiting Reactants! A Challenge Problem!
Alexxandr [17]

Answer:

a. Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

b. Fe2O3 is the limiting reactant.

c. 6.30 grams Fe

d. 52.6 %

Explanation:

Step 1: Data given

Mass of iron(III) oxide Fe2O3 = 9.00 grams

Mass of aluminium = 4.00 grams

Molar mass Fe2O3 = 159.69 g/mol

Aluminium molar mass = 26.98 g/mol

Step 2: The balanced equation

Fe2O3(s) + 2Al(s) → 2Fe(s) + Al2O3(s)

Step 3; Calculate Moles

Moles = mass / molar mass

Moles Fe2O3 = 9.00 grams / 159.69 g/mol

Moles Fe2O3 = 0.0564 moles

Moles Al = 4.00 grams / 26.98 g/mol

Moles Al = 0.148 moles

Step 4: Calculate limiting reactant

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

Fe2O3 is the limiting reactant. It will completely be consumed (0.0564 moles).  Al is in excess. There will react 0.0564*2 = 0.1128 moles

There will remain 0.148 - 0.1128 = 0.0352 moles Al

Step 5: Calculate moles Fe

For 1 mol Fe2O3 we need 2 moles Al to produce 2 moles Fe and 1 mol Al2O3

For 0.0564 moles Fe2O3 we'll have 2*0.0564 = 0.1128 moles Fe

Step 6: Mass of Fe

Mass Fe = 0.1128 moles * 55.845 g/mol

Mass Fe = 6.30 grams

Step 7: If you carried out this reaction and it actually produced 0.475 mL of molten iron (r = 6.98 g/mL), what is the percent yield of this reaction?

Density = mass / volume

Mass = density * volume

Mass = 6.98 g/mL * 0.475 mL

Mass = 3.3155 grams

Percent yield = (actual mass / theoretical mass) * 100%

Percent yield = (3.3155 /6.30 ) * 100 %

Percent yield = 52.6 %

3 0
2 years ago
Cyclobutane simplified structural formula please ​
daser333 [38]

Answer:

Cyclobutane is a cycloalkane and organic compound with the formula (CH2)4.

Explanation:

5 0
3 years ago
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