Answer:
![T=-75.59\°C](https://tex.z-dn.net/?f=T%3D-75.59%5C%C2%B0C)
Explanation:
Hello!
In this case, since we can treat neon as an ideal gas, it is possible for us to use the following equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
Whereas the temperature is out unknown, so we proceed as follows:
![T=\frac{PV}{nR}](https://tex.z-dn.net/?f=T%3D%5Cfrac%7BPV%7D%7BnR%7D)
However, we need the moles of neon in 0.02 kg as shown below:
![n=0.02kg*\frac{1000g}{1kg}*\frac{1mol}{20.17g} =0.992mol](https://tex.z-dn.net/?f=n%3D0.02kg%2A%5Cfrac%7B1000g%7D%7B1kg%7D%2A%5Cfrac%7B1mol%7D%7B20.17g%7D%20%20%3D0.992mol)
Thus, we obtain the following temperature in Kelvins:
![T=\frac{6.43atm*2.5L}{0.992mol*0.08206\frac{atm*L}{mol*K}} \\\\T=197.56K](https://tex.z-dn.net/?f=T%3D%5Cfrac%7B6.43atm%2A2.5L%7D%7B0.992mol%2A0.08206%5Cfrac%7Batm%2AL%7D%7Bmol%2AK%7D%7D%20%5C%5C%5C%5CT%3D197.56K)
Therefore, in degree Celsius it is:
![T=197.56-273.15\\\\T=-75.59\°C](https://tex.z-dn.net/?f=T%3D197.56-273.15%5C%5C%5C%5CT%3D-75.59%5C%C2%B0C)
Best regards!
It's any of the almost spherical concentric regions of matter that make up the earth and it's atmosphere, as the lithosphere and hydrosphere.
Hope this helps... If you could, could you mark my answer as brainliest? I'm trying to level lol
Solution :
An
reaction is a type of
in organic chemistry where the enol or an enolate ion reacts with the carbonyl compound and forms a
-hydroxyaldehyde or a
-hydroxyketone, and then followed by a dehydration to give conjugated enone.
Benzaldehyde reacts with methylketone and forms two products:
Answer: The molar mass of each gas
Explanation:
Mole fraction is the ratio of moles of that component to the total moles of solution. Moles of solute is the ratio of given mass to the molar mass.
![\text{Mole fraction of solute}=\frac{\text{Moles of solute}}{\text{Total Moles}}](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20solute%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20solute%7D%7D%7B%5Ctext%7BTotal%20Moles%7D%7D)
Suppose if there are three gases A, B and C.
a) ![\text{Mole fraction of A}=\frac{\text{Moles of A}}{\text{ Moles of (A+B+C)}}](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20A%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20A%7D%7D%7B%5Ctext%7B%20Moles%20of%20%28A%2BB%2BC%29%7D%7D)
b) ![\text{Mole fraction of B}=\frac{\text{Moles of B}}{\text{ Moles of (A+B+C)}}](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20B%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20B%7D%7D%7B%5Ctext%7B%20Moles%20of%20%28A%2BB%2BC%29%7D%7D)
c) ![\text{Mole fraction of C}=\frac{\text{Moles of C}}{\text{ Moles of (A+B+C)}}](https://tex.z-dn.net/?f=%5Ctext%7BMole%20fraction%20of%20C%7D%3D%5Cfrac%7B%5Ctext%7BMoles%20of%20C%7D%7D%7B%5Ctext%7B%20Moles%20of%20%28A%2BB%2BC%29%7D%7D)
moles of solute =![\frac{\text {given mass}}{\text {Molar mass}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Ctext%20%7Bgiven%20mass%7D%7D%7B%5Ctext%20%7BMolar%20mass%7D%7D)
Thus if mass of each gas is known , we must know the molar mass of each gas to know the moles of each gas.
Answer:
option c
Explanation:
as catalyst increases the reaction while activation energy is inversely proportional to rate of reaction, so option c is correct