Clay and water make a ______<br><br> a. solution<br> b.suspension<br> c. colloid

The following reaction is exothermic. C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g)C6H12O6(s)+6O2(g)⇌6CO2(g)+6H2O(g) Predict the effect (shi

elena55 [62]

Answer:

According to Le Chatelier's principle, increasing the reaction temperature of an exothermic reaction causes a shift to the left and decreasing the reaction temperature causes a shift to the right.

Explanation:

C6H12O6(s) + 6O2(g) ⇌6CO2(g) + 6H2O(g)

We are told that the forward reaction is exothermic, meaning heat is removed from the reacting substance to the surroundings.

According to Le Chatelier's principle,

1. for an exothermic reaction, on increasing the temperature, there is a shift in equilibrium to the left and formation of the product is favoured.

2. if the temperature of the system is decreased, the equilibrium shifts to right and the formation of the reactants is favoured.

3. if the reaction temperature is kept constant, the system is at equilibrium and there is no shift to the right nor to the left.

4 0

3 years ago

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Water and salt are compounds made of the combination of more than

inn [45]

Answer:

A. Because they are compounds, they cannot be pure substances.

Explanation:

The false statement from the given choices is that because they are compounds they cannot be pure substances. In fact, because they are compounds they are pure substances.

Pure substances are made up of elements and compounds and they have the following properties:

All parts are the same throughout
Composition is definite
They cannot easily be separated or broken
Separation by physical method is not easy
They have unique sets of physical and chemical properties.

8 0

3 years ago

Give the name of the following molecule. A compound with a total of six carbons with a double bond and the rest single bonds. Th

AlekseyPX

Answer:
The name of given molecule is 3-Methylpent-2-ene.

Explanation:
First of all a carbon chain of five carbons was drawn. Then a double bond was made between carbon 3 and 4 (starting from left). A methyl group was drawn at middle carbon which is at position 3.

Molecule sketched was named as,

1) A longest chain containing double bond was selected and numbering was started from the end closest to double bond. Hence,

2-Pentene or Pent-2-ene

2) The position of substituent was specified before the parent name, Hence,

3-Methyl-2-Pentene or 3-Methylpent-2-ene