Question

PLEASE HELP!! A gas has a volume of 7.9 L at a temperature of 222. K and pressure of 877 mmHg. What is the new temperature (in Celsius) if the volume becomes 10.41 L when the pressure drops to 0.327 atm?

Answer 1

Answer:

82.97 K

Explanation:

Applying,

PV/T = P'V'/T'................ Equation 1

Where P = initial pressure, T = Initial temperature, V = Initial Volume, P' = Final pressure, V' = Final Volume, T' = Final Temperature.

Make T' the subject of formula in equation 1

T' = P'V'T/PV................ Equation 2

From the question,

Given: P = 877 mmHg = (877×0.001316) atm = 1.154 atm, T = 222.2 K, V = 7.9 L, P' = 0.327 atm, V' = 10.41 L

Substitute these values into equation 2

T' = (0.327×10.41×222.2)/(1.154×7.9)

T' = 82.97 K

Hence the new temperature is 82.97 K