Answer:
Concentrated sulfuric acid is used as a catalyst, and has a dual role:
-Speeds up the reaction.
-Acts as a dehydrating agent, forcing the equilibrium to the right and resulting in a greater yield of ester.
Answer:
1.69 g Na₂O
General Formulas and Concepts:
<u>Chemistry - Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
Explanation:
<u>Step 1: Define</u>
0.0273 mol Na₂O
<u>Step 2: Identify Conversions</u>
Molar Mass of Na - 22.99 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Na₂O - 2(22.99) + 16.00 = 61.98 g/mol
<u>Step 3: Convert</u>
<u /> = 1.69205 g Na₂O
<u>Step 4: Check</u>
<em>We are given 3 sig figs. Follow sig fig rules and round.</em>
1.69205 g Na₂O ≈ 1.69 g Na₂O
Answer:
30g
Explanation:
According to this question, a sulfur-containing compound is said to contain 15 percent by mass of sulfur. This means that 15% of the total mass of the compound is the mass of sulfur in the compound.
The question further states that there is a total of 200g of the compound containing sulfur, this means that the mass of sulfur can be calculated this:
Mass of sulfur = 15% of 200g
15/100 × 200g
15 × 2
30g
Hence, there are 30g of sulfur in 200g of the sulfur containing compound.
The mass of the acid produced is 0.252 g from the information in the question.
<h3>What is neutralization?</h3>
The term neutralization refers to the reaction between an acid and a base that yileds salt and water only.
The equation of this reaction is; 2HCl + CaCO3 ----->CaCl2 + CO2 + H2O
Number of moles of CaCO3 = 0.350 g/100 g = 0.0035 moles
Since 2 moles of acid reacts with 1 mole of CaCO3
x moles acid reacts with 0.0035 moles of CaCO3
x = 0.007 moles
Mass of acid = 0.007 moles * 36 g/mol = 0.252 g
Learn more about neutralization: brainly.com/question/15395418