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stepan [7]
3 years ago
15

Which salt solution could contain 42 grams of solute per 100 grams of water at 40°c?

Chemistry
1 answer:
Harrizon [31]3 years ago
6 0

About 234 grams .nA 2M NaCl solution contains approximately 58.5g of salt. So to make two liters of a 2M solutions you would need 117g of salt dissolved in 2 liters of water.

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Calculate the standard enthalpy of formation of carbon disulfide (CS2) from it's elements, given that C(graphite) + O2(g) → CO2(
ch4aika [34]

Answer:

Standard enthalpy of formation of Carbon disulfide CS2 = 87.3 KJ/mol

Explanation:

forming CS2 means that it should in the product side

C(graphite) + O2 → CO2                  ΔH = -393.5

2S(rhombic) + 2O2 → 2SO2            ΔH = -296.4 x 2

CO2 + 2SO2 → CS2 + 3O2             ΔH = -1073.6 x -1

the second reaction is multiplied by 2 so that the SO2 and O2 can cancel out.

the third reaction is reversed (multiplied by -1) so that CS2 will be on the product side.

after adding the reaction and cancelling out similarities, the final reaction is: C(graphite) + 2S(rhombic) → CS2

Add ΔH to find the enthalpy of formation of CS2

ΔHf = (-393.5) + (-296.4 x 2) + (-1073.6 x -1) = 87.3 KJ/mol

be aware of signs

3 0
3 years ago
A car moved 20km East and 70km West. What is the distance?
Nutka1998 [239]

Answer:

50km

Explanation:

70km - 20km = 50 kilometers

6 0
3 years ago
What type of energy does water gain as it sits in the sun?
Studentka2010 [4]

Answer:

heat energy

Explanation:

water in the sun begins to get hot

8 0
4 years ago
Read 2 more answers
The empirical formula for a compound is C2H4NO. If its molar mass is 232.2 g/mol, what is the molecular formula of the compound?
Irina18 [472]

Empirical formula mass

  • C2H4NO
  • 2(12)+4(1)+14+16
  • 30+24+4
  • 58g/mol

Molar mass=232.2g/mol

Find n

  • Molar mass/Empirical formula mass
  • 232.2/58
  • 4

Molecular formula

  • n×Empirical formula
  • 4(C2H4NO)
  • C8H16(NO)_4
4 0
2 years ago
How much work is needed to assemble an atomic nucleus containing three protons (such as Be) if we model it as an equilateral tri
klio [65]

Answer:

2.16 MeV

Explanation:

To determine the amount of work done that is needed to assemble the atomic mass; we need to apply the equation;

U = \frac{3}{4 \pi E_o} (\frac{e^2}{r})

where:

\frac{1}{4 \pi E_o} = proportionality constant = (9*10^9N.m^2/C^2)

e = magnitude of the charge of each electron = (1.6*10^{-19} C)^2

r = length of each side of the vertex = (2.00*10^{-15}m)

So; replacing our values into above equation; we have:

U = 3\frac{(9*10^9N.m^2/C^2)(1.6*10^{-19} C)^2}{(2.00*10^{-15}m)}

U = 3.456 × 10 ⁻¹³ J

If we have to convert our unit from J to Mev; then we are going to have:

U = 3.456 × 10 ⁻¹³ J (\frac{1 MeV}{1.602*10^{-13}J})

U = 2.16 MeV

Therefore, the amount of work done needed to assemble an atomic nucleus =  2.16 MeV

8 0
3 years ago
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