Answer:
The object would weight 63 N on the Earth surface
Explanation:
We can use the general expression for the gravitational force between two objects to solve this problem, considering that in both cases, the mass of the Earth is the same. Notice as well that we know the gravitational force (weight) of the object at 3200 km from the Earth surface, which is (3200 + 6400 = 9600 km) from the center of the Earth:
Now, if the body is on the surface of the Earth, its weight (w) would be:
Now we can divide term by term the two equations above, to cancel out common factors and end up with a simple proportion:
Answer:
Explanation:
initial velocity, u = 8 m/s
vertical height, h = 1 m
θ = 40°
Let the horizontal distance is d and the time taken is t.
Use second equation of motion in vertical direction
h = ut + 1/2 at²
1 = 8 Sin 40 x t + 0.5 x 9.8 t²
1 = 5.14 t - 4.9t²
4.9t² - 5.14 t + 1 = 0
so, t = 0.26 s (smaller value)
So, the horizontal distance is
d = u cos 40 x t
d = 8 cos 40 x 0.26
d = 1.6 m
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Answer: 
Explanation:
Given
Mass 
Spring constant 
Compression in the spring 
When the mass leaves the spring, the elastic potential energy of spring is being converted into kinetic energy of mass i.e.
The kinetic energy of the mass is 1.102 J.
B. by taking measurements during an experiment
