Answer:
2.00 m/s²
Explanation:
Given
The Mass of the metal safe, M = 108kg
Pushing force applied by the burglar, F = 534 N
Co-efficient of kinetic friction,
= 0.3
Now,
The force against the kinetic friction is given as:

Where,
N = Normal reaction
g= acceleration due to the gravity
Substituting the values in the above equation, we get

or

Now, the net force on to the metal safe is

Substituting the values in the equation we get

or

also,
acceleration of the safe
Therefore, the acceleration of the metal safe will be
acceleration of the safe=
or
acceleration of the safe=
or
acceleration of the safe=
Hence, the acceleration of the metal safe will be 2.00 m/s²