The relation between the elements electro negativity, atomic radius, and ionization energy levels.
Answer:
In one mole of glucose, there are
6.022×1023
individual glucose molecules
Explanation:
Use PV=nRT to find V assuming n is one and R= 8.31 then use the answer to find P2
Answer: C2HNO3
Explanation: C = 27.59/12.011 = 2.297
H = 1.15/1.008 = 1.1409
N = 16.09/14.007 = 1.1487
O = 55.17/15.999 = 3.4483
Divide by smallest result:
C = 2
H=1
N=1
O = 3
Empirical formula = C2HNO3
