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MAXImum [283]
3 years ago
10

An object accelerating at 16 m/s/s doubles its mass and triples its net force acting on it. What will the new acceleration be? (

Just number no units)
Physics
1 answer:
nataly862011 [7]3 years ago
6 0

Answer:

24 m/s²

Explanation:

The given parameters are;

The initial acceleration of the object, a = 16 m/s²

Let 'm' represent the initial mass of the object

The initial force acting on the object, F = m × a

∴ F = 16 × m = 16·m

When the mass is doubled, we have;

The new mass of the object, m₂ = 2 × m = 2·m

When the net force acting on the object triples, we have;

The new net force acting on the object, F₂ = 3 × F = 3 × 16·m = 48·m

From F = m × a, we have;

a = F/m

∴ The new acceleration of the object, a₂ = F₂/m₂

From which, by plugging in the values, we have;

a₂ = 48·m/(2·m) = 24

The new acceleration of the object, a₂ = 24 m/s².

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If the charge remains the same but the radius of the sphere is doubled, the electric flux coming out of it will be
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Answer:

Explanation:

We shall apply Gauss's theorem for electric flux to solve the problem . According to this theorem , total electric flux coming out of a charge q can be given by the following relation .

∫ E ds = q / ε

Here q is assumed to be enclosed in a closed surface , E is electric intensity on the surface so

∫ E ds represents total electric flux passing through the closed surface due to charge q enclosed in the surface .

This also represents total flux coming out of the charge q on all sides .

This is equal to q / ε where ε is a constant called permittivity  which depends upon the medium enclosing the charge . For air , its value is 8.85 x 10⁻¹² .

If charge remains the same but radius of the sphere enclosing the charge is doubled , the flux coming out of charge will remain the same .

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1 ) charge q and

2 ) the permittivity of medium  ε  around .

4 0
3 years ago
Car's mass is 950kg. It's driven at 100km/h. How big is the kinetic energy?
polet [3.4K]

Answer:

4750000 J

Explanation:

Kinetic Energy= 1/2* mass* velocity²

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8 0
3 years ago
A spinning top initially spins at 16rad/s but slows down to 12rad/s in 18s, due to friction. If the rotational inertia of the to
Alex Ar [27]

Answer:

The  change  in angular momentum is \Delta  L  = 0.0016 \ kgm^2/s

Explanation:

From the question we are told that

      The initial angular velocity of the spinning top is  w_1  =  16 \ rad/s

      The angular velocity after it slow down is  w_2 =  12 \ rad/s

      The time  for it to slow down is  t =  18 \ s

       The rotational inertia due to friction is  I =  0.0004 \ kg \cdot m^2

 Generally the change in the angular momentum is  mathematically represented as  

         \Delta  L  =  I  *(w_1 -w_2)

substituting values  

        \Delta  L  =  0.0004  *(16 -12)

       \Delta  L  = 0.0016 \ kgm^2/s

5 0
3 years ago
What is the difference in the speed of the generator with a small magnet and a generator with a large magnet?
Delvig [45]
With a small magnet with a generator it will be taken up quickly because how small it is while with a big generator it would take more force for it for the generator to attach because the larger the magnet that heavier it will be because it is attached to the North Pole magnet
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Answer:

distance- I think it is 6 then the displacement is 13.41

Explanation:

4 0
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