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leva [86]
1 year ago
13

I started to solve this problem but I’m not sure on what to do next.

Physics
1 answer:
snow_tiger [21]1 year ago
7 0

ANSWER:

3408.81 kg

STEP-BY-STEP EXPLANATION:

Given:

v = 111 m/s

Ek = 21000000 J

We have that the formula for kinetic energy is as follows:

E_k=\frac{1}{2}\cdot m\cdot v^2

We substitute the values given in the exercise and solve for m (mass)

\begin{gathered} 21000000=\frac{1}{2}\cdot m\cdot111^2 \\ m=\frac{21000000\cdot2}{111^2} \\ m=3408.81\text{ kg} \end{gathered}

The mass of the helicopter is 3408.81 kilograms.

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Jackson throws a football 30 meters at a speed of 15 m/s. How long was the football in the air before Laurence caught it for tou
ch4aika [34]

Answer:

2s

Explanation:

Given parameters:

Distance  = 30m

Speed  = 15m/s

Unknown:

Time before Laurence caught it = ?

Solution:

To solve this problem;

    Speed  = \frac{disance }{time}  

 Time taken  = \frac{distance }{speed }   = \frac{30}{15}  = 2s

The time it takes is 2s

6 0
3 years ago
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A 150kg motorcycle starts from rest and accelerates at a constant rate along a distance of 350m. The applied force is 250N and t
notsponge [240]

A) The net force on the motorbike is 205.9 N

B) The acceleration of the motorbike is 1.37 m/s^2

C) The final speed is 5.2 m/s

D) The elapsed time is 3.80 s

Explanation:

A)

There are two forces acting on the motorbike:

- The applied force, F = 250 N, forward

- The frictional force, F_f, backward

The frictional force can be written as

F_f = \mu mg

where

\mu=0.03 is the coefficient of kinetic friction

m=150 kg is the mass of the motorbike

g=9.8 m/s^2 is the acceleration of gravity

Therefore the net force is given by

\sum F = F - F_f = F - \mu mg

And substituting, we find

\sum F=250 - (0.03)(150)(9.8)=205.9 N

2)

The acceleration of the motorbike can be found by using Newton's second law, which states that the net force is equal to the product between mass and acceleration:

\sum F = ma

where

m is the mass

a is the acceleration

In this problem, we have

\sum F = 205.9 N is the net force

m = 150 kg is the mass

Solving for a, we find the acceleration:

a=\frac{\sum F}{m}=\frac{205.9}{150}=1.37 m/s^2

C)

Since the motion of the motorbike is a uniformly accelerated motion, we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance covered

For this motorbike, we have:

u = 0 (it starts from rest)

a=1.37 m/s^2

s = 350 m

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(1.37)(9.8)}=5.2 m/s

4)

For this part of the problem, we can use the following suvat equation:

v=u+at

where

v is the final velocity

u is the initial velocity

a is the acceleration

t is the elapsed time

Here we have:

v = 5.2 m/s

u = 0

a=1.37 m/s^2

Solving for t, we find

t=\frac{v-u}{a}=\frac{5.2-0}{1.37}=3.80 s

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6 0
3 years ago
What is the velocity in meters per second of a runner who runs exactly 110 m toward the beach in 72 seconds.
KATRIN_1 [288]

1.53 m/s toward the beach

Explanation:

The magnitude of the velocity of the runner is given by:

v=\frac{d}{t}

where

d is the displacement of the runner

t is the time taken

In this case, d=110 m and t=72 s, so the velocity of the runner is

v=\frac{110 m}{72 s}=1.53 m/s

Velocity is a vector, so it consists of both magnitude and direction: we already calculate the magnitude, while the direction is given by the problem, toward the beach.

3 0
3 years ago
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A car accelerates from rest to 100 m/s in 20 s. What is its acceleration?
Dmitriy789 [7]
  • initial velocity=0m/s=u
  • Final velocity=v=100m/s
  • Time=t=20s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{100-0}{20}

\\ \sf\longmapsto Acceleration=\dfrac{100}{20}

\\ \sf\longmapsto Acceleration=5m/s^2

7 0
3 years ago
Express the angular velocity ω of the wheel in terms of the displacement d, the magnitude F of the applied force, and the moment
zhuklara [117]

Answer:

The angular velocity of the wheel in terms of d, F, and I is,  ω = d/t (F/I α)    s⁻¹

Explanation:

Given,

The angular velocity ω

The displacement d

The magnitude of the applied force, F

The moment of inertia of the wheel I = mr²

The angular velocity can be written as

                         ω = v /r

where,

                     v - linear velocity

                      r - radius of the wheel

                          ω = d/t (1/r)               (∵ v = d /t)

The force can be written as,

                          F = m a

                              = m α r                  (∵ a = α r)

Multiplying both sides by r

                          F r = m r² α

                           F r = I α                     (∵ I = mr²)

                              r = I α / F

Substituting in the above equation for ω

                          ω = d/t (F/I α)    s⁻¹

Hence, the angular velocity of the wheel in terms of d, F, and I is,  ω = d/t (F/I α)    s⁻¹

8 0
3 years ago
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