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Pavlova-9 [17]
3 years ago
10

A sample of an unknown compound is vaporized at . The gas produced has a volume of at a pressure of , and it weighs . Assuming t

he gas behaves as an ideal gas under these conditions, calculate the molar mass of the compound. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Likurg_2 [28]3 years ago
8 0

Answer:

The answer is "34 \ \frac{g}{mol}"

Explanation:

Please find the complete question in the attached file.

Formula:

\to PV = nRT\\\\n = \frac{mass}{MW} \\\\PV = \frac{mRT}{MW}\\\\MW = \frac{mRT}{(PV)}\\\\MW = \frac{(0.941)(0.082)(150+273)}{(1 \times 0.96)}

        = \frac{(0.941)(0.082)(423)}{(0.96)} \\\\= \frac{32.639526}{(0.96)} \\\\= 33.9995062\ \ \ or \ \ \ 34 \ \frac{g}{mol}

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7 0
3 years ago
Harry stores toxic chemical waste in a large steel tank that has only 15% of its volume underground. Jena lives in the wildernes
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3 years ago
When 3243. grams of iron (III) chloride are reacted with 511.8 grams of hydrosulfuric acid, which is the limiting reactant?
AleksAgata [21]

Answer:

Hydrosulfuric acid will act as limiting reactant.

Explanation:

Given data:

Mass of iron(III) chloride = 3243.0 g

Mass of hydrosulfuric acid = 511.8 g

Limiting reactant = ?

Solution:

Chemical equation:

2FeCl₃ + 3H₂S       →       Fe₂S₃ + 6HCl

Number of moles of iron(III) chloride:

Number of moles = mass/molar mass

Number of moles = 3243.0 g/ 162.2 g/mol

Number of moles = 20 mol

Number of moles of hydrosulfuric acid:

Number of moles = mass/molar mass

Number of moles = 511.8 g/ 34.1 g/mol

Number of moles = 15 mol

Now we will compare the moles of both reactant with products

                      FeCl₃          :          Fe₂S₃

                       2                :            1

                      20               :          1/2 ×20 = 10

                      FeCl₃          :            HCl

                       2                :              6

                      20               :          6/2 ×20 = 60

                      H₂S             :          Fe₂S₃

                       3                :            1

                      15               :          1/3 ×15 = 5

                      H₂S            :            HCl

                       3                :              6

                      15                :          6/3 ×15 = 30

Hydrosulfuric acid producing less number of moles of product thus, it will act as limiting reactant.

 

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