Answer:
Molar heat enthalpy of KBr = -19.89 kJ/mol
Explanation:
Change in temperature (Δt) = 0.370 K
Heat capacity = 2.71 kJ ⋅ K^-1
Heat absorbed by calorimeter = heat capacity × change in temperature
= 2.71× 0.370
= 1.0027 kJ
Molar mass of KBr = 119 g/mol
No. of moles of KBr = 6.00/119
= 0.0504 mol
Heat absorbed by the calorimeter is given by KBr.
Now calculate the heat released by per mol of KBr as follows:
Heat released by per mol of KBr = 1.0027 kJ / 0.0504 mol
=19.89 kJ/mol
Heat is released therefore, sign will be negative.
Molar heat enthalpy of KBr = -19.89 kJ/mol
The final volume of the nitrogen sample would be 790 mL
<h3>Charle's Law</h3>
According to Charles, at constant pressure, the volume of a gas is directly proportional to its temperature.
Mathematically: v1/t1 = v2/t2, where v1 and v2 = initial and final volume, and t1 and t2 = initial and final temperature.
In this case, t1 = 37 °C or 310 K, t2 = 77 °C or 350 K, v1 = 700 mL
Thus: v2 = v1 x t2/t1 = 700 x 350/310 = 790 mL
More on Charle's law can be found here: brainly.com/question/16927784
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Answer:
150.000 g
Explanation:
The law of conservation of mass states that the mass of reactants and products of a reaction must be equal to one another.
In other words, for this case:
- Mass of KOH + Mass of HCl = Mass of Products
We are given all required data to<u> calculate the mass of the KOH solution</u>:
- Mass of KOH + 250.000 g = 400.000 g
Answer:
Explanation:The equation for this is F = -GmM/R^2 where the minus sign says the force is attractive m is 10 kg, M is 20 kg and R is 5 meters. If you crunch the numbers you get an answer of:
22 grams, 5 x 3 x 1 = 15 / volume. mass (330) ÷ 15 (volume) = 22 grams (density)