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IRINA_888 [86]
3 years ago
7

HELP PLZ!!! A sample contains only the compound CaCl2 and water. When it is dried, its weight decreases from 5.00g to 4.24g. Wha

t is the mass percentage of water in the original sample? Round to three significant figures.
Chemistry
2 answers:
steposvetlana [31]3 years ago
7 0

Answer:

Mass of water is 18.01528 g/mol. I hope this helps

Explanation:

AfilCa [17]3 years ago
5 0

Answer:is 15.2%

Explanation:

Got it wrong and this the correct answer it told me

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Drag each label to the correct location on the table.
AleksAgata [21]

Explanation:

1) Boyle's Law: This law states that pressure is inversely related to the volume occupied by the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

  • When the size of the chamber is increased the volume occupied the gas will increase with which pressure exerted by the gas will decrease down.
  • When we press the inflated balloon the pressure on the gas is increased with which volume of the occupied by the gas inside the balloon decreased.

2) Charles' Law: This law states that volume occupied by the gas is directly related to the temperature of the gas at constant pressure and number of moles.

V\propto T    (At constant pressure and number of moles)

  • The size of the balloon deceases because the in winters the temperature decreases with which volume of the gas present in the balloon also decreases.
  • When the flexible closed container is heated the temperature of the gas inside the container increases with which the volume occupied by the gas in the container will increase resulting in expanding of container.

3) Avogadro's Law: This law states that volume occupied by the gas is directly related to the number of moles of the gas at constant pressure and temperature.

V\propto n   (At constant temperature and pressure)

When we blow air into the balloon the umber of air particles increases with which the volume of the gas inside the balloon also increases resulting in increase in size of the balloon.

3 0
3 years ago
What is the pH of this solution?
Vesnalui [34]

Answer:

pH = 11.216.

Explanation:

Hello there!

In this case, according to the ionization of ammonia in aqueous solution:

NH_3+H_2O\rightleftharpoons NH_4^++OH^-

We can set up its equilibrium expression in terms of x as the reaction extent equal to the concentration of each product at equilibrium:

Kb=\frac{[NH_4^+][OH^-]}{[NH_3]} \\\\1.80x10^{-5}=\frac{x*x}{0.150-x}

However, since Kb<<<1 we can neglect the x on bottom and easily compute it via:

1.80x10^{-5}=\frac{x*x}{0.150}\\\\x=\sqrt{1.80x10^{-5}*0.150}=1.643x10^{-3}M

Which is also:

[OH^-]=1.643x10^{-3}M

Thereafter we can compute the pOH first:

pOH=-log(1.643x10^{-3}M)\\\\pOH=2.784

Finally, the pH turns out:

pH=14-2.784\\\\pH=11.216

Regards!

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