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3 years ago

How many molecules of HBr are present in 42.5 grams of HBr

1 answer:

4 0

HBr molar mass is 80.9 g/mol
this means in 80.9 g - 1 mol of HBr
1 mol consists of 6.022 x 10²³ molecules of HBr
that means in 80.9 g HBr there are 6.022 x 10²³ molecules of HBr
therefore in 42.5 g of HBr there are 6.022 x 10²³/80.9 * 42.5
the number of HBr molecules are therefore - 3.16 x 10²³ HBr molecules

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2 years ago

3. A student carries out the clay-catalyzed dehydration of cyclohexanol starting with 10 moles of cyclohexanol and obtains 500 m

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$49.45~%$

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With this value we can calculate the grams:

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Now, we have as a product 500 mL of $C_6H_1_0$ . If we use the density value (0.811 g/mL). We can calculate the grams of product:

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Finally, with these values we can calculate the yield:

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See figure 1

I hope it helps!

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