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Aleks04 [339]
3 years ago
13

On a coordinate plane, solid circles appear at the following points: (negative 5, negative 3), (negative 4, negative 4), (negati

ve 2, 2), (1, 3), (1, negative 2), (2, 1), (5, negative 4). Which ordered pair can be removed so that the resulting graph represents a function? (–2, 2) (1, 3) (5, –4) (–4, –4)
Mathematics
2 answers:
7nadin3 [17]3 years ago
8 0

Answer:

(1 , 3) B.)

Step-by-step explanation:

Serjik [45]3 years ago
5 0

Answer:

(1,3)

Step-by-step explanation:

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Terrence walks 1/3mile in 1/12 hour. What is his walking speed in Miles per hour?
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Read 2 more answers
Find the dimensions of a rectangle with area 512 m2 whose perimeter is as small as possible. (If both values are the same number
Masja [62]

Answer:

<h2>√512 by √512 </h2>

Step-by-step explanation:

Length the length and breadth of the rectangle be x and y.

Area of the rectangle A = Length * breadth

Perimeter P = 2(Length + Breadth)

A = xy and P = 2(x+y)

If the area of the rectangle is 512m², then 512 = xy

x = 512/y

Substituting x = 512/y into the formula for calculating the perimeter;

P = 2(512/y + y)

P = 1024/y + 2y

To get the value of y, we will set dP/dy to zero and solve.

dP/dy = -1024y⁻² + 2

-1024y⁻² + 2 = 0

-1024y⁻² = -2

512y⁻² = 1

y⁻² = 1/512

1/y² = 1/512

y²  = 512

y = √512 m

On testing for minimum, we must know that the perimeter is at the minimum when y = √512

From xy = 512

x(√512) = 512

x = 512/√512

On rationalizing, x = 512/√512 * √512 /√512

x = 512√512 /512

x = √512 m

Hence, the dimensions of a rectangle is √512 m  by √512 m

5 0
4 years ago
An increased number of colleges have been using online resources to research applicants. According to a study from last​ year, 3
Aneli [31]

Answer:

D. H0​: p ≤0.36 H1​: p>0.36

$$(Right tail test) Z_{\alpha}=Z_{0.1}=1.28155

Z_p=-0.25516

D. Reject H0. There is sufficient evidence to support the hypothesis that the proportion of admissions officers who visit an applying​ students' social networking page has increased in the past year

Step-by-step explanation:

To solve this problem, we run a hypothesis test about the population proportion.

$$Sample proportion: $\bar P=0.47\\Sample size n=100$\\Significance level \alpha=0.10$\\(Left tail test) Z_{1-\alpha}=Z_{0.90}=-1.28155$\\(Right tail test) Z_{\alpha}=Z_{0.1}=1.28155$\\(Two-tailed test) $Z_{1-\alpha/2}=Z_{0.95}=-1.64485$ and $ Z_{\alpha/2}=Z_{0.05}=1.64485\\\\

The appropriate hypothesis system for this situation is:

H_0:\pi_0=0.35\\H_a:\pi_0 > 0.35\\\\$Proportion in the null hypothesis is:\\\pi_0=0.35\\\\

$$The test statistic is $Z=\frac{(\bar P-\pi_0)\sqrt{n}}{\sqrt{\pi_0(1-\pi_0)}}\\$The calculated statistic is Z_c=\frac{(0.47-0.35)\sqrt{100}}{\sqrt{0.35(1-0.35)}}=-0.25516\\p-value = P(Z \geq Z_c)=0.01620\\\\

Since, the calculated statistic Z_c is greater than critical Z_{\alpha}, the null hypothesis should be rejected. There is enough statistical evidence to state that the proportion of admissions officers who visit an applying​ students' social networking page has increased in the past year.

5 0
3 years ago
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