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2 years ago

What is the momentum of a 1, 500 kg car traveling at 3m/s?

Physics

2 answers:

ruslelena [56]2 years ago

6 0

4,500 kgm/s bc 1,500x3

marusya05 [52]2 years ago

3 0

<h3>Answer: D) 4,500 kg m/s</h3>

========================================

Work Shown:

To find the momentum, we multiply the mass and the velocity.

m = mass = 1500 kg

v = velocity = 3 m/s

p = momentum

p = m*v

p = (1500 kg)*(3 m/s)

p = (1500*3) kg m/s

p = 4500 kg m/s

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A positive point charge q1 = +5.00 × 10−4C is held at a fixed position. A small object with mass 4.00×10−3kg and charge q2 = −3.

Lelechka [254]

Answer:

Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.

Explanation:

Energy conservation law: In isolated system the amount of total energy remains constant.

The types of energy are

Kinetic energy.
Potential energy.

Kinetic energy $=\frac{1}{2} mv^2$

Potential energy = $\frac{Kq_1q_2}{d}$

Here, q₁= +5.00×10⁻⁴C

q₂=-3.00×10⁻⁴C

d= distance = 4.00 m

V = velocity = 800 m/s

Total energy(E) =Kinetic energy+Potential energy

$=\frac{1}{2} mv^2$ + $\frac{Kq_1q_2}{d}$

$=\frac{1}{2} \times 4.00\times 10^{-3}\times(800)^2 +\frac{9\times10^9\times 5\times10^{-4}\times(-3\times10^{-4})}{4}$

=(1280-337.5)J

=942.5 J

Total energy of a system remains constant.

Therefore,

E $=\frac{1}{2} mv^2$ + $\frac{Kq_1q_2}{d}$

$\Rightarrow 942.5 = \frac{1}{2} \times 4 \times10^{-3} \times V^2 +\frac{9\times10^{9}\times5\times 10^{-4}\times(-3\times 10^{-4})}{0.2}$

$\Rightarrow 942.5 = 2\times10^{-3}v^2 -6750$

$\Rightarrow 2 \times10^{-3}\times v^2= 942.5+6750$

$\Rightarrow v^2 = \frac{7692.5}{2\times 10^{-3}}$

$\Rightarrow v= 1961.19$ m/s

Therefore the speed of q₂ is 1961.19 m/s when it is 0.200 m from from q₁.

5 0

3 years ago

If you are using a wrench to loosen a very stubborn nut, you can make the job easier by using a "cheater pipe." This is a piece

pentagon [3]

Answer:

Explained

Explanation:

The cheater pipe extends the wrench in radial direction, providing a larger momentum for the force you exert.

For a given force the torque exerted with the cheater pipe is larger.

Mathematically we can write that

τ = r×F and τ'= r'×F

now since r'> r

⇒ F'>F

5 0

3 years ago

Read 2 more answers

Calculate the angle for the third-order maximum of 580-nm wavelength yellow light falling on double slits separated by 0.100 mm.

alekssr [168]

<u>Answer:</u> The angle of diffraction is 0.498°

<u>Explanation:</u>

To calculate the angle of diffraction, we use the equation given by Bragg, which is:

$n\lambda =2d\sin \theta$

where,

n = order of diffraction = 3

$\lambda$ = wavelength of the light = $580nm=5.80\times 10^{-7}m$ (Conversion factor: $1m=10^{9}nm$ )

d = spacing between the crystal planes = 0.100 mm = $1.0\times 10^{-4}$ (Conversion factor: 1 m = 1000 mm)

$\theta$ = angle of diffraction = ?

Putting values in above equation:

$3\times 5.80\times 10^{-7}=2\times 1.00\times 10^{-4}\sin \theta\\\\\sin \theta = 0.0087\\\\\theta=\sin ^{-1} (0.0087)=0.498$

Hence, the angle of diffraction is 0.498°

6 0

3 years ago

What is the work done when a 400.n force is use to lift a 400.n object 3.5 meters strait up

alexandr1967 [171]

Answer:

i think it's 1400

Explanation:

w = Force x displacement

w = 400 x 3.5

3 0

3 years ago

What is the best insulator?

Aleonysh [2.5K]

Answer:

Explanation:

All others conduct electricity and heat.

6 0

2 years ago

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