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boyakko [2]
3 years ago
11

What is the momentum of a 1, 500 kg car traveling at 3m/s?

Physics
2 answers:
ruslelena [56]3 years ago
6 0
4,500 kgm/s bc 1,500x3
marusya05 [52]3 years ago
3 0
<h3>Answer: D)  4,500 kg m/s</h3>

========================================

Work Shown:

To find the momentum, we multiply the mass and the velocity.

m = mass = 1500 kg

v = velocity = 3 m/s

p = momentum

p = m*v

p = (1500 kg)*(3 m/s)

p = (1500*3) kg m/s

p = 4500 kg m/s

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Which type of reaction does this diagram represent?
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Nuclear fusion because atomic nuclei combine to form a heavier nucleus. Option A is correct.

<h3>What is nuclear fusion?</h3>

The process by which two or more tiny nuclei unite to generate a bigger nucleus is known as a nuclear fusion reaction.

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Jeff puts on a leather jacket over his sweater. The sweater becomes negatively charged. Which statements about Jeff’s situation
KiRa [710]

The sweater has a tendency to attract electrons.

The leather jacket has a lower tendency to attract electrons than the sweater.

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The sweater and the leather jackets are made up of distinct fabrics that based on their minutest particles called an atom.

An atom is made up of sub-atomic particles of protons, neutrons and electrons.

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3 0
3 years ago
A Ferris wheel on a California pier is 27 m high and rotates once every 32 seconds in the counterclockwise direction. When the w
Leto [7]

A) 140 degrees

First of all, we need to find the angular velocity of the Ferris wheel. We know that its period is

T = 32 s

So the angular velocity is

\omega=\frac{2\pi}{T}=\frac{2\pi}{32 s}=0.20 rad/s

Assuming the wheel is moving at constant angular velocity, we can now calculate the angular displacement with respect to the initial position:

\theta= \omega t

and substituting t = 75 seconds, we find

\theta= (0.20 rad/s)(75 s)=15 rad

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B) 2.7 m/s

The tangential speed, v, of a point at the egde of the wheel is given by

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Substituting into the equation, we find

v=(0.20 rad/s)(13.5 m)=2.7 m/s

6 0
3 years ago
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