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boyakko [2]
3 years ago
11

What is the momentum of a 1, 500 kg car traveling at 3m/s?

Physics
2 answers:
ruslelena [56]3 years ago
6 0
4,500 kgm/s bc 1,500x3
marusya05 [52]3 years ago
3 0
<h3>Answer: D)  4,500 kg m/s</h3>

========================================

Work Shown:

To find the momentum, we multiply the mass and the velocity.

m = mass = 1500 kg

v = velocity = 3 m/s

p = momentum

p = m*v

p = (1500 kg)*(3 m/s)

p = (1500*3) kg m/s

p = 4500 kg m/s

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¿Cuál será la potencia de una bombilla conectada a una red de energía eléctrica de 440V, si la corriente que circula por el circ
goblinko [34]

Answer:

La potencia de la bombilla es de 1056 W.

Explanation:

La potencia de la bombilla se puede calcular usando la siguiente ecuación:

P = I*V

En donde:

P: es la potencia

I: es la corriente = 2,4 A

V: es la diferencia de potencial = 440 V

Entonces, la potencia es:

P = I*V = 2,4 A*440 V = 1056 W

Por lo tanto, la potencia de la bombilla es de 1056 W.

Espero que te sea de utilidad!

3 0
3 years ago
Which pair correctly identifies the strongest and weakest fundamental forces,
Kay [80]

Answer: Option B.

Strong nuclear force Gravity.

Explanation:

Nuclear force is the strongest force while Gravity is the weakest force. Strong nuclear force is the strongest force because it's act and hold atoms of matter together. It also binds neutrons and protons together to form atomic nuclei and it's has strength of 1.

Gravity is considered the weak force out of the four fundamental forces because it has a very small strength of 10^40 than electromagnetic force.

7 0
3 years ago
An electron with a charge of -1.6 × 10-19 coulombs experiences a field of 1.4 × 105 newtons/coulomb. What is the magnitude of th
RSB [31]
F=Eq. Just sub in the values and you are done.
7 0
4 years ago
Read 2 more answers
An object starts from rest and falls freely for 40. meters near the surface of planet P. If the time of fall is 4.0 seconds, wha
Sergeu [11.5K]
Let's use the equations for rectilinear motion. One particular equation is:

d = v₀t +(1/2)at²

Since it has been mentioned that the object starts from rest, then v₀ = 0. Substituting the values,

40 m = (0)(4 s) + (1/2)(a)(4 s)²
Solving for a,
a = 5 m/s²

<em>Therefore, the acceleration due to gravity is 5 m/s².</em>
6 0
4 years ago
The distance between the ruled lines on a diffraction grating is 1900 nm. The grating is illuminated at normal incidence with a
SashulF [63]

Answer:

3.28 degree

Explanation:

We are given that

Distance between the ruled lines on a diffraction grating, d=1900nm=1900\times 10^{-9}m

Where 1nm=10^{-9} m

\lambda_2=400nm=400\times10^{-9}m

\lambda_1=700nm=700\times 10^{-9}m

We have to find  the angular width of the gap between the first order spectrum and the second order spectrum.

We know that

\theta=sin^{-1}(\frac{m\lambda}{d})

Using the formula

m=1

\theta_1=sin^{-1}(\frac{1\times700\times 10^{-9}}{1900\times 10^{-9}})

\theta=21.62^{\circ}

Now, m=2

\theta_2=sin^{-1}(\frac{2\times400\times 10^{-9}}{1900\times 10^{-9}})

\theta_2=24.90^{\circ}

\Delta \theta=\theta_2-\theta_1

\Delta \theta=24.90-21.62

\Delta \theta=3.28^{\circ}

Hence, the angular width of the gap between the first order spectrum and the second order spectrum=3.28 degree

6 0
3 years ago
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