2 years ago

How far away is the closest star?

Physics

2 answers:

sukhopar [10]2 years ago

8 0

Answer: Proxima Centauri is the closet star about 40,208,000,000,000 km away.

Explanation:

balu736 [363]2 years ago

4 0

Answer:

The closest star is about 25,300,000,000,000 miles (39,900,000,000,000 kilometers) away

Explanation:

You might be interested in

when an object falls, eventually the force of air resistance (drag) = the force of gravity. This is called ____

jarptica [38.1K]

Terminal velocity dkdkmfocmdpdmfpfmfl

4 0

3 years ago

Could a nucleus that has one proton but no neutrons exist?

diamong [38]

Yes, but there is only 1 atom like that and is is hydrogen. Hydrogen is the only element that could have a nucleus with one proton and no neutrons exist.

8 0

3 years ago

Give three examples from your life of magnetic force.

Margaret [11]

Headphones, refrigerator magnets, and compasses

Hope that was helpful.

4 0

3 years ago

Read 2 more answers

The atomic nucleus contains two subatomic particles, the proton and the neutron. Atoms of different elements have different numb

9966 [12]

The answer is option A .

7 0

3 years ago

Read 2 more answers

Devise an exponential decay function that fits the given data, then answer the accompanying questions. Be sure to identify the

7nadin3 [17]

Answer:

22145.27733 ft

124984.76055 ft

Explanation:

The equation of pressure is

$P=P_0e^{-kh}$

where,

$P_0$ =Atmospheric pressure = 800 mbar

k = Constant

h = Altitude = 35000 ft

$P=\dfrac{1}{3}P_0$

$\dfrac{1}{3}P_0=P_0e^{-k35000}\\\Rightarrow \dfrac{1}{3}=e^{-k35000}\\\Rightarrow 3=e^{k35000}\\\Rightarrow ln3=k35000\\\Rightarrow k=\dfrac{ln3}{35000}\\\Rightarrow k=3.13\times 10^{-5}$

Now

$P=\dfrac{1}{2}P_0$

$ln2=kh\\\Rightarrow h=\dfrac{ln2}{k}\\\Rightarrow h=\dfrac{ln2}{3.13\times 10^{-5}}\\\Rightarrow h=22145.27733\ ft$

The altitude will be 22145.27733 ft

$P=0.02P_0$

$0.02P_0=P_0e^{-kh}\\\Rightarrow 0.02=e^{-3.13\times 10^{-5}h}\\\Rightarrow ln0.02=-3.13\times 10^{-5}h\\\Rightarrow h=\dfrac{ln0.02}{-3.13\times 10^{-5}}\\\Rightarrow h=124984.76055\ ft$

The elevation is 124984.76055 ft

6 0

3 years ago