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Reptile [31]
2 years ago
7

How far away is the closest star?

Physics
2 answers:
sukhopar [10]2 years ago
8 0

Answer: Proxima Centauri is the closet star about 40,208,000,000,000 km away. 

Explanation:

balu736 [363]2 years ago
4 0

Answer:

The closest star is about 25,300,000,000,000 miles (39,900,000,000,000 kilometers) away

Explanation:

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Which of the following is an idea that robert hutchings goddard introduced in his “further developments” to his research "a meth
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3 years ago
What may thermal energy stores also be called?<br><br> PLEASE REALLY NEED THE HELP!
ollegr [7]

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3 0
3 years ago
(b) Find a point between the two charges on the horizontal line where the electric potential is zero. (Enter your answer as meas
aleksley [76]

Complete Question: A charge q1 = 2.2 uC is at a distance d= 1.63m from a second charge q2= -5.67 uC. (b) Find a point between the two charges on the horizontal line where the electric potential is zero. (Enter your answer as measured from q1.)

Answer:

d= 0.46 m

Explanation:

The electric potential is defined as the work needed, per unit charge, to bring a positive test charge from infinity to the point of interest.

For a point charge, the electric potential, at a distance r from it, according to Coulomb´s Law and the definition of potential, can be expressed as follows:

V = \frac{k*q}{r}

We have two charges, q₁ and q₂, and we need to find a point between them, where the electric potential due to them, be zero.

If we call x to the distance from q₁, the distance from q₂, will be the distance between both charges, minus x.

So, we can find the value of x, adding the potentials due to q₁ and q₂, in such a way that both add to zero:

V = \frac{k*q1}{x} +\frac{k*q2}{(1.63m-x)} = 0

⇒k*q1* (1.63m - x) = -k*q2*x:

Replacing by the values of q1, q2, and k, and solving for x, we get:

⇒ x = (2.22 μC* 1.63 m) / 7.89 μC = 0.46 m from q1.

3 0
3 years ago
Read 2 more answers
PLEASE ANSWER ASAP, WILL MARK BRAINLIEST***
Andreyy89
The answer is to your question is c
7 0
2 years ago
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