Determine the value of the resultant and its location from O.see attach image.
1 answer:
Answer:
Explanation:
In the x direction the force will be
½(-w₀)L/2 = -¼w₀L
acting ⅔(L/2) = L/3 below the x axis.
In the y direction the force will be
½(-w₀)L + ½w₀L/2 = -¼w₀L
the magnitude of the resultant will be
F = w₀L √((-¼)² + (-¼)²) = w₀L√⅛
in the direction
θ = arctan(-¼w₀L / -¼w₀L) = 225°
to find the distance, we balance moments
(w₀L√⅛)[d] = ½(w₀)L[⅔L] + ¼w₀L[⅔L/2] - ¼w₀L[L - ⅓L/2]
(√⅛)[d] = ½ [⅔L] + ¼ [⅔L/2] - ¼ [L - ⅓L/2]
(√⅛)[d] = ½[⅔L] + ¼[⅔L/2] - ¼[L - ⅓L/2]
(√⅛)[d] = ⅓L + ⅟₁₂L - ¼L + ⅟₂₄L
(√⅛)[d] = 5L/24
d = 5L/24 / (√⅛)
d = 5√⅛L/3
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Answer:
Resistance = 68.23 Ω
Explanation:
Let's start off by remembering the fact that when resistors are connected in series, their resistances is added up to find the total resistance.
The equation for resistance using resistivity is given below:
Resistance = Resistivity * Length / Area
where Length = x
Resistivity = 3x^5
and Area = = 8.04 * 10^(-8) meter squared
Substituting in the value of resistivity, length and area we get:
Resistance =
Resistance =
Since resistance in series is added, we can simply integrate this formula over the length (x = 0 to x = 0.2) to get the total resistance.
Resistance =
Resistance =
Resistance = 68.23 Ω