There's a short handy formula for that.
If the object is just dropped and not tossed, and it's not affected by air resistance on the way down, then the distance it falls in T seconds is
D = (1/2) (gravity) (T²)
For this problem . . .
176.4 m = (1/2) (9.8 m/s²) (T²)
Divide each side by (4.9 m/s²) :
T² = (176.4 m) / (4.9 m/s²)
T² = (36 s²)
Take the square root of each side:
<em>T = 6 seconds</em>
Answer: Contact force
a. Applying break in a vehicle.
d. The speed of ball rolling on ground is reduced
Non contact force
b. A coconut falling from a coconut tree.
c. The planets revolving around the sun.
Explanation:
The contact force is the force which exerts when one object or entity comes in contact with other object or entity. For example, on application of break the vehicle stops, the force is applied on the breaks to stop the vehicle. The ball rolling on the ground the speed reduces so the application of force on the ground also reduces.
The non contact force is the force one object exerts on the other without coming in direct contact with the other object. The force exerted by one object on other due to gravity is a non contact force. The coconut falling on the ground and planets revolving around the sun are examples of non contact force due to gravity.
Yes because the acceleration of an object as produced by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force, and inversely proportional to the mass of the object.
The core or a place called the epic center
