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KiRa [710]
3 years ago
6

Help me please I’m struggling very bad

Chemistry
2 answers:
djyliett [7]3 years ago
5 0

Answer:

Answer in explanation below!

Explanation:

Box 1 : Eukarya - this is the domain of organisms that have cells enclosed within a nuclear envelope

Box 2: Protista - any eukaryotic organism that is not an animal, plant or fungus

Box 3: Fungi - they can be single celled ( unicellular ) or multicellular

Box 4: Eubacteria - they are prokaryotic microorganisms

I hope this helps, good luck!

USPshnik [31]3 years ago
3 0

Answer:

I answered on the other thread! <3

Explanation:

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In a titration experiment, hcl and lioh solutions were used. the initial volume of hcl was 1.25ml and lioh was 2.65 ml. the fina
aliya0001 [1]
Answer is: <span>the molarity of HCl is </span>0.097 M.
Chemical reaction: LiOH + HCl → LiCl + H₂O.
V(HCl) = 13.60 mL - 1.25 mL = 12.35 mL.
V(LiOH) = 11.20 mL - 2.65 mL = 8.55 mL.
c(LiOH) = 0.140 M.
From chemical reaction: n(LiOH) : n(HCl) = 1 : 1.
c(HCl) · V(HCl) = c(LiOH) · V(LiOH).
c(HCl) = 8.55 mL · 0.140 M / 12.35 mL.
c(LiOH) = 0.097 M. 
8 0
3 years ago
Sound waves are transverse mechanical waves. <br><br> True<br> False
allochka39001 [22]

False

Explanation:

Sound waves are longitudinal mechanical waves.

Mechanical waves are waves that requires a medium to propagate them.

  • A transverse wave is a wave that is propagated perpendicularly to its source.
  • An example is electromagnetic radiation.
  • A longitudinal wave is a wave that is directed parallel to their source.
  • Sound wave is a longitudinal wave.
  • It has series of rarefaction and compression along its travel path.
  • Rarefaction are areas of sparse particles.
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learn more:

Sound wave brainly.com/question/3619541

#learnwithBrainly

7 0
3 years ago
2. A chemical analysis of a sample provides the following elemental data:
Vadim26 [7]

Answer:

C3 H6 O2

Explanation:

first divide their mass by their respective molar mass, we get:

30.4 moles of C

61.2 moles of H

20.25 moles of O

now divide everyone by the smallest one of them then we get

C= 1.5

H= 3

O= 1

since our answer of C is not near to any whole number so we will multiply all of them by 2

so,

C3 H6 O2 is our answer

3 0
2 years ago
Calculate the pH of a buffer solution prepared by mixing 60.0 mL of 1.00 M lactic acid and 25.0 mL of 1.00 M sodium lactate.
marshall27 [118]
This problem could be solved easily using the Henderson-Hasselbach equation used for preparing buffer solutions. The equation is written below:

pH = pKa + log[(salt/acid]

Where salt represents the molarity of salt (sodium lactate), while acid is the molarity of acid (lactic acid). 

Moles of salt = 1 mol/L * 25 mL * 1 L/1000 mL = 0.025 moles salt
Moles of acid = 1 mol/L* 60 mL * 1 L/1000 mL = 0.06 moles acid
Total Volume = (25 mL + 60 mL)*(1 L/1000 mL) = 0.085 L

Molarity of salt = 0.025 mol/0.085 L = 0.29412 M
Molarity of acid = 0.06 mol/0.085 L = 0.70588 M

Thus,
pH = 3.86 + log(0.29412/0.70588)
pH = 3.48
4 0
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What does a biochemical solar panel have
Viktor [21]
I agree with the person on top have a beautiful day:)
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